Question

尝试使用where约束从多个嵌套关系中获取数据：

模特用户：

    <?php

    use Illuminate\Auth\UserInterface;
    use Illuminate\Auth\Reminders\RemindableInterface;
    use Illuminate\Database\Eloquent\SoftDeletingTrait;
    use Zizaco\Entrust\HasRole;

  class User extends BaseModel implements UserInterface, RemindableInterface {
  use HasRole;

protected $fillable = array('username', 'password');
/**
 * The database table used by the model.
 *
 * @var string
 */
protected $table = 'users';

/**
 * The attributes excluded from the model's JSON form.
 *
 * @var array
 */
protected $hidden = array('password');
protected $dates = ['deleted_at'];
protected $softDelete = true;  

 public function editor()
{
    return $this->hasOne('User_Editor', 'user_id');
}
?>

Model User_Editor：

   <?php

   class User_Editor extends BaseModel {
/**
 * The database table used by the model.
 *
 * @var string
 */
protected $table = 'users_editors';

/**
 * The attributes excluded from the model's JSON form.
 *
 * @var array
 */
protected $hidden = array();

/**
 * Defiens the column names of fillable columns.
 *
 * @var array
 */
protected $fillable = array();

/**
 * Relationships
 */
public function credentials()
{
    return $this->hasMany('User_Editor_Credential', 'user_editor_id');
}

public function specialties()
{
    return $this->hasMany('User_Editor_Specialty', 'user_editor_id');
}
?>

Model User_Editor_Credentials：

    <?php

 class User_Editor_Credential extends BaseModel {
/**
 * The database table used by the model.
 *
 * @var string
 */
protected $table = 'users_editors_credentials';

/**
 * The attributes excluded from the model's JSON form.
 *
 * @var array
 */
protected $hidden = array();

/**
 * Defiens the column names of fillable columns.
 *
 * @var array
 */
protected $fillable = array();
 }

Model User_Editor_Specialties：

    <?php

     class User_Editor_Specialty extends BaseModel {
/**
 * The database table used by the model.
 *
 * @var string
 */
protected $table = 'users_editors_specialties';

/**
 * The attributes excluded from the model's JSON form.
 *
 * @var array
 */
protected $hidden = array();

/**
 * Defiens the column names of fillable columns.
 *
 * @var array
 */
protected $fillable = array();
 }

返回

select * from User，User_Editor，User_Editor_Credentials，User_Editor_Specialty where User_Editor_Specialty.specialty In（array）。

到目前为止，我已尝试过，

    $this->data['editors'] = User::with(['editor.credentials.specialties' => function($q) use($data){
            $q->whereIn('specialty',$data);
        }])
        ->get();

但这会引发对未定义方法专业的错误调用。请指导，谢谢。

Answer 1

对于那些可能长期试图找到解决嵌套关系的方法的人，以及如果你用whereIn编写连接条件（由于Laravel中的错误而调用未定义的方法），请在下面找到ans，

    $editors = User::with(['editor.credentials','editor.specialties']);
    $this->data['editors'] = $editors->whereHas('editor', function($q) use ($a_data){
       $q->whereHas('specialties',function($sq) use($a_data){
            $sq->whereIn('specialty',$a_data);
       });
    })->get();

Answer 2

更新：PR刚刚合并到4.2，所以现在可以在has方法中使用点嵌套表示法（->has('relation1.relation2) ->whereHas('relation1.relation2, ..）

您的点标记关系必须在逻辑上链接：

`with(['editor.credentials', ' editor.specialties' => function ....

您试图在specialties型号上搜索User_Editor_Credential关系。

根据评论：

User::with(['editor.credentials','editor.specialties'])
    ->whereHas('editor' => function($q) use ($data){
       $q->whereHas('specialties' => function($q) use ($data){
          $q->whereIn('specialty',$data);
       });
    })->get();

或者如果您使用我的公关https://github.com/laravel/framework/pull/4954

User::with(['editor.credentials','editor.specialties'])
    ->whereHas('editor.specialties' => function($q) use ($data){
        $q->whereIn('specialty',$data);
    })->get();

它将返回与users相关的editor.specialties匹配的所有whereIn，以及相关的editor及其相关credentials和specialties（后者不会被过滤掉）

雄辩的多个嵌套关系与约束

2 个答案: