我正在编写一个函数,它在更多维度上索引一维数组。用户可以选择索引的深度。
例如
var store = ["Alaska", "Alabama", "North Korea", "South Korea"];
用户可以选择例如深度1.这意味着它将通过字符串
的第一个字符串进行索引index["a"] = ["Alaska", "Alabama"];
index["n"] = ["North Korea"];
如果用户选择深度= 2,那么它将是2D数组,索引是两个开始的字符
index["a"]["l"] = ["Alaska", "Alabama"];
等
如何完成一个可以在JavaScript中填充变量Dimension数组的函数?
var indexthis = function(store,depth)
{
if(depth == "undefined")
{depth =1;}
//any Suggestions to go on?
};
问候
答案 0 :(得分:1)
此功能:
function indexWord(index, word, letters) {
var letter;
if (!letters) letters = word.split("");
while (letters.length) {
letter = letters.shift().toLowerCase();
if (!(letter in index)) index[letter] = {_items: []};
index[letter]._items.push(word);
indexWord(index[letter], word, letters);
}
}
这样叫:
var store = ["Alaska", "Alabama", "North Korea", "South Korea"],
index = {}, i;
for (i = 0; i < store.length; i++) {
indexWord(index, store[i]);
}
为您提供以下索引:
{
a: {
_items: ["Alaska", "Alabama"],
l: {
_items: ["Alaska", "Alabama"],
a: {
_items: ["Alaska", "Alabama"],
s: {
_items: ["Alaska"],
k: {
_items: ["Alaska"],
a: {
_items: ["Alaska"]
}
}
},
b: {
_items: ["Alabama"],
a: {
_items: ["Alabama"],
m: {
_items: ["Alabama"],
a: {
_items: ["Alabama"]
}
}
}
}
}
}
},
n: {
_items: ["North Korea"],
o: {
_items: ["North Korea"],
r: {
_items: ["North Korea"],
t: {
_items: ["North Korea"],
h: {
_items: ["North Korea"],
" ": {
_items: ["North Korea"],
k: {
_items: ["North Korea"],
o: {
_items: ["North Korea"],
r: {
_items: ["North Korea"],
e: {
_items: ["North Korea"],
a: {
_items: ["North Korea"]
}
}
}
}
}
}
}
}
}
}
},
s: {
_items: ["South Korea"],
o: {
_items: ["South Korea"],
u: {
_items: ["South Korea"],
t: {
_items: ["South Korea"],
h: {
_items: ["South Korea"],
" ": {
_items: ["South Korea"],
k: {
_items: ["South Korea"],
o: {
_items: ["South Korea"],
r: {
_items: ["South Korea"],
e: {
_items: ["South Korea"],
a: {
_items: ["South Korea"]
}
}
}
}
}
}
}
}
}
}
}
}
其中index["a"]["l"]._items
或index.a.l._items
可用于访问["Alaska", "Alabama"]
。
答案 1 :(得分:0)
这似乎符合您的要求:
function createIndex(store, depth) {
var index = {};
depth = depth || 1;
// loop over each item in the store
store.forEach(function (item) {
var lower = item.toLowerCase(),
current = index,
char;
// loop over the characters, building the store structure
for (i = 0; i < depth; i++) {
char = lower.substr(i, 1);
// add the key, if it doesn't exist
if (!current[char]) {
current[char] = (i == (depth - 1) ? [] : {});
}
// update the object reference
current = current[char];
}
// now add the item
current.push(item);
});
return index;
}