Question

有人能指出为什么这个插入触发器没有将新行插入IVRTestB表吗？

  If Object_ID('MyTrig3', 'TR') IS Not Null
  Drop Trigger MyTrig3;
  GO

  Alter Trigger MyTrig3
  On dbo.IVRTest
  After Insert, update
    AS
  Begin
  SET NOCOUNT ON;
  Insert Into [dbo].[IVRTestB]  
  (IVRAID, IVRName, DayNumber, OpenFlag)  
  Select 
     'i.IVRAID', 'i.IVRName', 'i.DayNumber', 'i.OpenFlag'
          From inserted i
      INNER JOIN dbo.IVRTestB b
      On i.IVRAID = b.IVRAID
      END

Answer 1

通过将Inserted的每一列放入单引号，您可以有效地将字符串文字插入到目标表中 - 而不是列值！

请改用此代码：

INSERT INTO [dbo].[IVRTestB] (IVRAID, IVRName, DayNumber, OpenFlag)  
   SELECT
      i.IVRAID, i.IVRName, i.DayNumber, i.OpenFlag    -- *NO* single quotes here!!!!
   FROM   
      inserted i
   -- change this WHERE clause to insert those rows that AREN'T alredy in IVRTestB !
   WHERE
      i.IVRAID NOT IN (SELECT DISTINCT IVRAID FROM dbo.IVRTestB)

Answer 2

  Alter Trigger MyTrig3
  On dbo.IVRTest
  After Insert
    AS
  Begin
  SET NOCOUNT ON;
       IF EXISTS ( SELECT  
                      1  
                  FROM  
                      INSERTED  
                  WHERE  
                      INSERTED.DayNumber IS NULL )  
  Insert Into 
  [dbo].[IVRTestB]  
  (IVRAID, 
  IVRName, 
  DayNumber, 
  OpenFlag)  
  Select 
     i.IVRAID,
      i.IVRName, 
      i.DayNumber, 
      i.OpenFlag
          From inserted i
       WHERE  
                 INSERTED.DayNumber IS NULL  
      END

Answer 3

Mohan将

你改变了几乎工作，我只需要将not nulls更改为not null并将别名更改为I

   Alter Trigger MyTrig3
  On dbo.IVRTest
  After Insert
    AS
  Begin
  SET NOCOUNT ON;
       IF EXISTS ( SELECT  
                      1  
                  FROM  
                      INSERTED  
                  WHERE  
                      INSERTED.DayNumber IS NOT NULL )  
  Insert Into 
  [dbo].[IVRTestB]  
  (IVRAID, 
  IVRName, 
  DayNumber, 
  OpenFlag)  
  Select 
     i.IVRAID,
      i.IVRName, 
      i.DayNumber, 
      i.OpenFlag
          From inserted i
       WHERE  
                 i.DayNumber IS NOT NULL  
      END

插入触发器不在其他表中插入新行

3 个答案: