我需要检查java home是否在我的系统中可用,如果java home不可用,则需要显示错误消息并且想要检查java版本是否小于1.7。如果它大于1.7它需要显示错误。这是可能的。目前我使用下面的脚本。可以任何一个建议mADe脚本需要什么更改。或者是否需要任何新脚本。 提前致谢
@echo off
setlocal enableextensions disabledelayedexpansion
:: possible locations under HKLM\SOFTWARE of JavaSoft registry data
set "javaNativeVersion="
set "java32ON64=Wow6432Node\"
:: for variables
:: %%k = HKLM\SOFTWARE subkeys where to search for JavaSoft key
:: %%j = full path of "Java Runtime Environment" key under %%k
:: %%v = current java version
:: %%e = path to java
set "javaDir="
set "javaVersion="
for %%k in ( "%javaNativeVersion%" "%java32ON64%") do if not defined javaDir (
for %%j in (
"HKLM\SOFTWARE\%%~kJavaSoft\Java Runtime Environment"
) do for /f "tokens=3" %%v in (
'reg query "%%~j" /v "CurrentVersion" 2^>nul ^| find /i "CurrentVersion"'
) do for /f "tokens=2,*" %%d in (
'reg query "%%~j\%%v" /v "JavaHome" 2^>nul ^| find /i "JavaHome"'
) do ( set "javaDir=%%~e" & set "javaVersion=%%v" )
)
if not defined javaDir (
echo Java not found
) else (
echo JAVA_HOME="%javaDir%"
echo JAVA_VERSION="%javaVersion%"
)
endlocal
pause
答案 0 :(得分:0)
您可以使用LSS
,GRT
和EQU
等来批量比较字符串。
EQU
=等于NEQ
=不等于LSS
=少于LEQ
=小于或等于GTR
=大于GEQ
=大于或等于由于您已获得%javaVersion%
中的版本信息,因此您只需显示错误消息。
您可以将代码修改为:
if not defined javaDir (
echo Java not found
) else (
echo JAVA_HOME="%javaDir%"
echo JAVA_VERSION="%javaVersion%"
if "%javaVersion%" LSS "1.7" (
echo Java version is too low!
goto exit
)
if "%javaVersion%" GTR "1.7" (
echo JAVA version is too high!
goto exit
)
)
:exit
endlocal
pause