Question

我做了一个简单的tkinter GUI，我想要一个浏览按钮，但它似乎没有出现

#!/usr/bin/env python      
import Tkinter as tk       

class Application(tk.Frame):              
    def __init__(self, master=None):
        tk.Frame.__init__(self, master)   
        self.grid()                       
        self.quit_program()

    def quit_program(self):
        self.quitButton = tk.Button(self, text='Quit',
          command=self.quit)            
        self.quitButton.grid()

    def browse_file(self):
        self.browseButton = tk.Button(self, text='Browse',
          command=tkFileDialog.askopenfilename(parent=root,title='Open file to encrypt'))
        self.browseButton.grid()

app = Application()                       
app.master.title('Sample application')    
app.mainloop()

Answer 1

#!/usr/bin/env python      
import Tkinter as tk
import tkFileDialog

class Application(tk.Frame):              
    def __init__(self, master=None):
        tk.Frame.__init__(self, master)   
        self.grid()                       
        self.quit_program()
        self.browse_file()
        self.file_opt = options = {}
        options['defaultextension'] = '.txt'
        options['filetypes'] = [('musicfiles', '.mp3'),('vediofiles', '.mp4')]

        options['parent'] = self
        options['title'] = 'This is a title'

    def quit_program(self):
        self.quitButton = tk.Button(self, text='Quit',
          command=self.quit)            
        self.quitButton.grid()

    def browse_file(self):
        self.browseButton = tk.Button(self, text='Browse',command=self.askopenfile)
        self.browseButton.grid()
    def askopenfile(self):
        return tkFileDialog.askopenfile(**self.file_opt )

app = Application()                       
app.master.title('Sample application')    
app.mainloop()

Answer 2

代码中的三个错误

什么是tkFileDialog？你有进口吗？通过在文件顶部添加import tkFileDialog来导入它
什么是root？将root更改为self。
command中的tk.Button参数并不是按照您的方式使用。您不应该在命令参数中调用该方法。您应该指定单击按钮时要调用的方法。在您的示例中，您告诉tkinter，调用tkFileDialog.askopenfilename()返回的值而不是调用tkFileDialog.askopenfilename。所以用另一种方法替换它或使用lambda。 command=lambda : tkFileDialog.askopenfilename(parent=root,title='Open file to encrypt')

浏览未显示Python GUI Tkinter

2 个答案: