Question

我正在尝试编写一个获取用户信息并将其添加到列表中的程序，然后我想总计有多少用户输入，但我无法做到。我试过运行一个累加器，但是我得到TypeError：不支持的操作数类型为+：＆＃39; int＆＃39;和＆＃39; str＆＃39;。

def main():
    #total = 0

    cel_list = []

    another_celeb = 'y'

    while another_celeb == 'y' or another_celeb == 'Y':

        celeb = input('Enter a favorite celebrity: ')

        cel_list.append(celeb)

        print('Would you like to add another celebrity?')

        another_celeb = input('y = yes, done = no: ')


        print()
    print('These are the celebrities you added to the list:')
    for celeb in cel_list:
        print(celeb)
        #total = total + celeb
        #print('The number of celebrities you have added is:', total)



main()

这是没有累加器的所需输出，但我仍然需要将输入加在一起。我已经评论了累加器。

Enter a favorite celebrity: Brad Pitt
Would you like to add another celebrity?
y = yes, done = no: y

Enter a favorite celebrity: Jennifer Anniston
Would you like to add another celebrity?
y = yes, done = no: done

These are the celebrities you added to the list:
Brad Pitt
Jennifer Anniston
>>>

提前感谢任何建议。

Answer 1

Total是一个整数（在之前声明为）

    total = 0

正如错误代码所示，您正在尝试使用字符串连接整数。这是不允许的。要通过此错误，您可以：

    ## convert total from int to str
    output = str(total) + celeb
    print(" the number of celebrities you have added is', output)

甚至更好，您可以尝试使用字符串格式

    ##output = str(total) + celeb
    ## using string formatting instead
    print(" the number of celebrities you have added is %s %s', %  (total, celeb))

我希望这对你有用

Answer 2

您可以使用len()函数获取Python列表中的条目数。所以，只需使用以下内容：

print('These are the celebrities you added to the list:')
for celeb in cel_list:
    print(celeb)
total = len(cel_list)
print('The number of celebrities you have added is: ' + str(total))

请注意最后两行的缩进缩小 - 在完成名人姓名的打印后，您只需要运行一次。

Answer 3

Python是一种动态类型语言。因此，当您键入total = 0时，变量total变为整数，即Python根据变量包含的值为变量赋值。

您可以使用type(variable_name)检查python中任何变量的类型。

len（object）返回整数值。

for celeb in cel_list:
    print(celeb)

#end of for loop
total = 0
total = total + len(cel_list) # int + int
print('The number of celebrities you have added is:', total)

困惑于为什么我不能一起添加字符串

3 个答案: