Question

当我使用文字字符串化的JSON对象时，所有工作都按预期工作

Index.cshtml（使用文字ajax字符串$ .ajax WORKS）

var searchObject = new Object();
searchObject.Thing1 = '42';
searchObject.Thing2 = '43';
searchObject.Thing3 = '44';

var searchSerialized = JSON.stringify(searchObject);
alert(searchSerialized);
$.ajax(
{
    url: '/api/auditApi',
    type: "Post",
    contentType: "application/json; charset=utf-8",
    data: '{\'Thing1\':\'42\',\'Thing2\':\'43\',\'Thing3\':\'44\'}',
    dataType: 'json',
    success: function (result) {
                       $(".kendoAudit").data("kendoGrid").dataSource = new kendo.data.DataSource({ data: result });
                       $(".kendoAudit").data("kendoGrid").dataSource.read();
                       $(".kendoAudit").data("kendoGrid").refresh();
                   },
                   error: function (xhr, ajaxOptions, thrownError) {
                       alert('Status: ' + xhr.status + ', Error Thrown: ' + thrownError);
                   }
               });

但是，当我使用内联创建的序列化对象时，它会将null传入post post

Index.cshtml（对象创建为内联并传递给$ .ajax FAILS）

var searchObject = new Object();
searchObject.Thing1 = '42';
searchObject.Thing2 = '43';
searchObject.Thing3 = '44';

var searchSerialized = JSON.stringify(searchObject);
alert(searchSerialized);
$.ajax(
{
    url: '/api/auditApi',
    type: "Post",
    contentType: "application/json; charset=utf-8",
    data: searchSerialized,  //I have tried concatenating with + '' also
    dataType: 'json',
    success: function (result) {
                       $(".kendoAudit").data("kendoGrid").dataSource = new kendo.data.DataSource({ data: result });
                       $(".kendoAudit").data("kendoGrid").dataSource.read();
                       $(".kendoAudit").data("kendoGrid").refresh();
                   },
                   error: function (xhr, ajaxOptions, thrownError) {
                       alert('Status: ' + xhr.status + ', Error Thrown: ' + thrownError);
                   }
               });

控制器

public HttpResponseMessage Post([FromBody]string value)
{
    try
    {
        var results = JsonConvert.DeserializeObject<dynamic>(value);
    }
    catch (Exception ex) 
    {
        // throws because value is null.
    }
}

我确信在转换过程中我遗漏了很多东西。

调试行：alert(searchSerialized);显示我期待的内容

Answer 1

您可以直接将数据输入模型。当发布序列化对象（不再是字符串）时，MVC会自动将其绑定到正确的模型。

现在改变你的行动方法。

    public class SearchObject
    {
        public int Thing1 { get; set; }
        public int Thing2 { get; set; }
        public int Thing3 { get; set; }
    }

    [HttpPost]
    public ActionResult Test(SearchObject searchObject)
    {
        return View();
    }

发布JSON对象传递的是null而不是对象

1 个答案: