Question

我正在使用SQL Server 2008，并且遇到了我需要的方式返回行的麻烦。以下查询返回以下数据。

查询：

SELECT 
    [DATE_PULL] as d, 
    [OWNER] as label, 
    SUM(VM_COUNT) as value 
FROM 
    [VCENTER_INFO_HIST] 
GROUP BY 
    OWNER, DATE_PULL

结果输出：

+-------------------------------------------------+
|    D       |   label        |  value            |
+-------------------------------------------------+
| 06/30/2014 |    Test1       |       443         |
| 06/30/2014 |    Test2       |       456         |
| 06/30/2014 |    Test3       |       487         |
| 07/07/2014 |    Test1       |       1024        |
| 07/07/2014 |    Test2       |       2056        |
| 07/07/2014 |    Test3       |       2076        |
+-------------------------------------------------+

我需要输出看起来像这样：

+---------------------------------------------------------------------+
|    D       |   Test1        |      Test2        |      Test3        |
+---------------------------------------------------------------------+
| 06/30/2014 |    443         |       456         |       487         | 
| 07/07/2014 |    1024        |       2056        |       2076        |
+---------------------------------------------------------------------+

任何帮助将不胜感激！

Answer 1

您可以使用PIVOT：

执行此操作

SELECT *
FROM Table1
PIVOT (MAX(value) FOR label IN (Test1,Test2,Test3))pvt

演示：SQL Fiddle

使用您的查询：

SELECT *
FROM (SELECT [DATE_PULL] as d, [OWNER] as label, sum(VM_COUNT) as value 
      FROM [VCENTER_INFO_HIST] 
      GROUP BY OWNER, DATE_PULL
      )sub
PIVOT (MAX(value) FOR label IN (Test1,Test2,Test3))pvt

Answer 2

使用pivot

SELECT * FROM [VCENTER_INFO_HIST]
pivot (sum(VM_COUNT) for OWNER in ([Test1], [Test2], [Test3])) as pvt

SQL子查询或联合

2 个答案: