Question

运行Eloquent连接查询时，我得到了一些意想不到的结果。使用完全相同的查询得到两个不同的结果。一个用DB :: raw（）运行，第二个用Eloquent运行。

在Eloquent查询中，匹配

的用户

where squad_user.leave_time >= seasons.start_time

缺失，不会包含在结果集中。匹配

的用户

or squad_user.leave is null

但是，

将被包括在内。

这是两个查询结果的唯一区别。原始查询实际上产生了所需的结果集。

真的让我感到困惑的是，如果我查看了Laravel和MySQL的查询日志，我在运行raw和Eloquent查询时会得到完全相同的查询。

原始查询（运行Eloquent查询时从查询日志中获取的实际查询）

return \DB::select(\DB::raw('
        select users.*
        from users
        inner join squad_user on users.id = squad_user.user_id
        inner join seasons on squad_user.squad_id = seasons.squad_id
        where squad_user.join_time <= seasons.end_time
        and (squad_user.leave_time >= seasons.start_time or squad_user.leave_time is null)
        and seasons.id = :seasonId
    '),
    ['seasonId' => 3]
);

雄辩查询

return User::join('squad_user', 'users.id', '=', 'squad_user.user_id')
           ->join('seasons', 'squad_user.squad_id', '=', 'seasons.squad_id')
           ->where('squad_user.join_time', '<=', 'seasons.end_time')
           ->where(function ($query)
           {
               $query->where('squad_user.leave_time', '>=', 'seasons.start_time')
                     ->orWhereNull('squad_user.leave_time');
           })
           ->where('seasons.id', 3)
           ->get(['users.*']);

Laravel的Eloquent查询日志

select `users`.*
from `users`
inner join `squad_user` on `users`.`id` = `squad_user`.`user_id`
inner join `seasons` on `squad_user`.`squad_id` = `seasons`.`squad_id`
where `squad_user`.`join_time` <= seasons.end_time
and (`squad_user`.`leave_time` >= seasons.start_time or `squad_user`.`leave_time` is null)
and `seasons`.`id` = 3
{"bindings":["seasons.end_time","seasons.start_time",3],"time":0.38,"name":"mysql"}

关于Eloquent查询的MySQL的general_log

select `users`.*
from `users`
inner join `squad_user` on `users`.`id` = `squad_user`.`user_id`
inner join `seasons` on `squad_user`.`squad_id` = `seasons`.`squad_id`
where `squad_user`.`join_time` <= ?
and (`squad_user`.`leave_time` >= ? or `squad_user`.`leave_time` is null)
and `seasons`.`id` = ?

原始查询中MySQL的general_log

select users.*
            from users
            inner join squad_user on users.id = squad_user.user_id
            inner join seasons on squad_user.squad_id = seasons.squad_id
            where squad_user.join_time <= seasons.end_time
            and (squad_user.leave_time >= seasons.start_time or squad_user.leave_time is null)
            and seasons.id = ?

我很感激这里有任何指示，因为我很失落。

Answer 1

where绑定第3个参数并将其作为字符串处理，除非您不使用原始语句告诉它。 DB::raw或whereRaw适合您：

return User::join('squad_user', 'users.id', '=', 'squad_user.user_id')
       ->join('seasons', 'squad_user.squad_id', '=', 'seasons.squad_id')
       ->where('squad_user.join_time', '<=', DB::raw('seasons.end_time'))
       ->where(function ($query)
       {
           $query->where('squad_user.leave_time', '>=', DB::raw('seasons.start_time'))
                 ->orWhereNull('squad_user.leave_time');
       })
       ->where('seasons.id', 3)
       ->get(['users.*']);

Answer 2

从Laravel Verion 5.2开始，您还可以使用whereColumn来验证两列是否相等（或将比较运算符传递给该方法）：

->whereColumn('squad_user.join_time', '<=', 'seasons.end_time')

使用与DB :: raw和Eloquent相同的查询的不同结果

2 个答案: