Question

您好我在Android中执行网址有问题，我确信它与方括号有关，但我找不到任何解决方案。欢迎大家提出意见。

  protected String doInBackground(String... arg0) {
        try {


            int indexdevice = 12;
            String uuu = URLEncoder.encode  ("http://<ipaddress>/ZWaveAPI/Run/devices[2].instances[0].commandClasses[0x25].Set(255)", "UTF-8");
            HttpClient Client = new DefaultHttpClient();
            String SetServerString = "";
            HttpGet httpget = new HttpGet(uuu);
            ResponseHandler<String> responseHandler = new BasicResponseHandler();
            SetServerString = Client.execute(httpget,responseHandler);
            Log.v("NAS", "--------- amount is  " + SetServerString);

        } 
            catch (Exception ex) 
            {
            Log.v("NAS",String.valueOf(ex));
            }

我得到的错误是：

 07-08 12:37:33.970: V/NAS(1800): java.lang.IllegalStateException: 
Target host must not be null, or set in parameters. scheme=null, host=null,

Answer 1

您正在编码完整网址的网址，包括http和主机名。那不会奏效。只需在主机地址之后对部件进行编码：

String uuu = "http://<ipaddress>/"+URLEncoder.encode  ("ZWaveAPI/Run/devices[2].instances[0].commandClasses[0x25].Set(255)", "UTF-8");

Answer 2

http：//可能正在编码尝试类似的东西 String foo = foo.replaceFirst（“http：//”，“”）; foo =“http：//”+ foo

方括号在android中导致URL字符串错误

2 个答案: