Question

//in SomeClass
pprivate Client _client = new Client();
public Dictionary<string, Channel> Channels = new Dictionary<string, Channel>();

public SomeClass()
{
    Channels.Add("main", _client.GetChannel("#channelName"));
    Channels.Add("secundary", _client.GetChannel("#secondChannelName"));
}

//in Client
public Channel GetChannel(string channelName)
{ //return a channel specific to this Client.
}

当我创建SomeClass()时，字典会从当前Channel返回中填充_client.GetChannel()个对象。它将Channel保存到词典中，但我希望它将-method-添加到词典中;并且每次调用字典都会返回当前_client.GetChannel()在其被调用的那一刻返回的内容。

例如，当调用Channels["main"]时，我希望它为我调用Client.GetChannel("#channelName")并返回它返回的任何内容。

我怎样才能做到这一点？

Answer 1

将频道名称存储在字典中：

//in SomeClass
public Client Client = new Client();
public Dictionary<string, string> Channels = new Dictionary<string, string>();

public SomeClass()
{
    Channels.Add("main", "#channelName");
    Channels.Add("secundary", "#secondChannelName");
}

//in Client
public Channel GetChannel(string channelName)
{ //return a channel specific to this Client.
}

然后，为了获取Channel对象，请调用GetChannel：

string channelName;
Channels.tryGetValue("main", out channelName);
Channel thisChannel = Client.GetChannel(channelName);

如果您从SomeClass外部执行此操作（因为客户端是私有的），您可以从SomeClass公开一个公共方法来执行相同的操作：

// to run it in a different class:
Channel thisChannel = someClassInstance.GetChannelObject("#main");

// in SomeClass:
public Channel GetChannelObject(string channelID) {
    string channelName;
    Channels.tryGetValue(channelID, out channelName);
    Channel thisChannel = Client.GetChannel(channelName);
    return(thisChannel);
}

Answer 2

你可以这样做：

public Dictionary<string, Func<Channel>> Channels
    = new Dictionary<string, Func<Channel>>();

public SomeClass()
{
    Channels.Add("main", () => _client.GetChannel("#channelName"));
    Channels.Add("secundary", () => _client.GetChannel("#secondChannelName"));
}

然后你可以这样称呼它：

var main = Channels["main"]();

或者：

var main = Channels["main"].Invoke();

如何使Dictionary返回方法结果？

2 个答案: