我已经搜索了这个问题的答案,但尚未找到类似的问题或答案。如果这是一个"重新询问"我很抱歉。
基本上我的问题是这样的:我的父页面里面有一个iframe,而iframe里面是一个包含我的.js文件的php页面,其中包含我的AJAX。我想在iframe中点击按钮来创建AJAX请求并更新iframe。据我所知,我已经正确设置了但是当我试图回应我的$ _POST(我也试过GET)变量来测试它们时它们永远不会改变。这是我的代码:
父:
<!DOCTYPE html>
<html style = "height: 100%; width: 100%;">
<head>
<title>Employee Web Service</title>
<link rel="stylesheet" type="text/css" media="screen, projection" href="lib/css/main.css" />
<script src="lib/scripts/jquery-2.0.3.min.js" type="text/javascript"></script>
</head>
<body style = "height: 100%;">
<div id = "header">
<img src = "images/header.png" id = "headerLogo">
</div>
<div id = "nav">
<ul>
<li><a href = "home.php" target = "content">Home</a></li>
<li><a href = "#">Modules</a>
<ul>
<li><a href = "test.php?id=1" target = "content">Module 1</a></li>
<li><a href = "test.php?id=2" target = "content">Module 2</a></li>
<li><a href = "test.php?id=3" target = "content">Module 3</a></li>
<li><a href = "test.php?id=4" target = "content">Module 4</a></li>
</ul>
</li>
<li><a href = "scores.php" target = "content">Scores</a></li>
<li><a href = "calendar.php" target = "content">Calendar</a></li>
<li><a href = "logout.php">Logout</a></li>
</ul>
</div>
<div id = "content">
<iframe src = "home.php" name = "content" id = "frameContent"></iframe>
<script>
$(document).ready(function(){
$('#frameContent').load(function(){
$('#frameContent').contents().find('head').append('<link href="lib/css/iframe.css" rel="stylesheet" type="text/css" />');
});
});
</script>
</div>
</body>
</html>
iframe中的test.php:
<?php
if(isset($_POST['begin'])){
$test = true;
echo($_POST['begin']);
} else if (isset($_POST['backToSlides'])){
echo($_POST['backToSlides']);
}
?>
<head>
<script src="lib/scripts/jquery-2.0.3.min.js" type="text/javascript"></script>
<script src = "lib/scripts/testScript.js" type="text/javascript"></script>
</head>
<body>
<div id = "startTest" <?php if(isset($test)){echo 'style = "visibility: hidden; disabled: true;"';}?> >
<h1>Test <?php echo $id; ?></h1>
<form id = "begin">
<input type = "submit" name = "backToSlides" value = "Go back" style = "background: #B9090B;">
<input type = "submit" name = "begin" value = "Start Test" style = "background: #09913A;">
</form>
</div>
<div id = "testContent"></div>
</body>
testScript.js:
$(document).ready(function(){
$('input[name = "backToSlides"], input[name = "begin"]').click(function(event){
event.preventDefault();
post = $(this).attr("name") + "=" + $(this).val();
$.ajax({
url: "/test.php",
type: "POST",
data: post, //Data purposely not serialized due to the way submit-type input field values are handled
success: function(){
console.log("Processing request...");},
error: function(){
console.log("Error submitting request");}
});
});
});
此ALWAYS调用成功函数,但我从未在post数据中看到提交按钮的值。我知道他们正在被正确地传递到ajax呼叫,因为我已经尝试呼叫提醒($(this).attr(&#34; name&#34;)+&#34; =&#34; + $(this).val())我得到&#34; key = value&#34;的预期结果。
非常感谢快速响应!
答案 0 :(得分:1)
您需要阻止默认浏览器提交表单,否则因为您要提交相同的网址,它只会刷新iframe页面
$('input[name = "backToSlides"], input[name = "begin"]').click(function(event){
event.preventDefault();
/* ajax */
})
答案 1 :(得分:0)
将iframe更改为div并改为使用jquery .load()函数
父页面上的:
<script>
$(document).ready(function(){
$("a").click(function(event){
event.preventDefault();
tar = $(this).attr("href");
$("#content").load(tar);
);
);
</script>
我可以将所有<a>
标记转换为<div>
标记,将光标更改为鼠标悬停时的指针,这样我就不必阻止默认操作并扫描'href '属性,但现在这就行了。