touchesBegan没有被召唤

时间:2014-07-07 23:15:36

标签: ios objective-c uiview

我使用UIPicker填充UITextField而不是键盘。这很好但我现在无法关闭UIPicker。我希望能够点击屏幕上的任意位置并关闭UIPicker。我已经尝试了每种触摸方法,无人会触发。

setUserInteractionEnabled:YES。 不确定它是否有所作为,但我使用的是StoryBoard

我应该在AppDelegate中设置一些内容来监听触摸吗?

这是我的.h

 #import <UIKit/UIKit.h>

@interface RNMemberTableViewController : UITableViewController<UIPickerViewDataSource, UIPickerViewDelegate, UITextFieldDelegate>

@property (weak, nonatomic) IBOutlet UIPickerView *behaviorPicker;
@property (nonatomic, weak) IBOutlet UIDatePicker *dateOfRecordPicker;
@property (nonatomic, strong) NSArray *behaviorLevels;
@property (weak, nonatomic) IBOutlet UITextField *behaviorTextField;

@end

这里有一些实现......

- (void)viewDidLoad
{
    [super viewDidLoad];
    [self.view setUserInteractionEnabled:YES];
    [self buildBehaviorPicker];
    NSLog(@"Member View");
}

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
    NSLog(@"test");
    [self.view touchesBegan:touches withEvent:event];
    UITouch *touch = [touches anyObject];
    int tCount = touch.tapCount;
    NSLog(@"Touched %d", tCount);
}

- (void) buildBehaviorPicker
{
    behaviorLevels = [[NSArray alloc] initWithObjects:@"Unsatisfactory", @"Needs Improvement", @"Satisfactory", @"Outstanding", nil];

    UIPickerView *pickerView = [[UIPickerView alloc] init];
    pickerView.dataSource = self;
    pickerView.delegate = self;
    [pickerView selectRow:2 inComponent:0 animated:NO];
    self.behaviorTextField.inputView = pickerView;


}

提前致谢 -Bob

3 个答案:

答案 0 :(得分:6)

您可以随时尝试以下操作:

-(void)viewDidLoad
{
    [super viewDidLoad];

    UITapGestureRecognizer *tapGestureRecognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tapReceived:)];
    [tapGestureRecognizer setDelegate:self];
    [self.view addGestureRecognizer:tapGestureRecognizer];
}

-(void)tapReceived:(UITapGestureRecognizer *)tapGestureRecognizer
{
    // do something, like dismiss your view controller, picker, etc., etc.
}

希望这会有所帮助......

答案 1 :(得分:0)

您可以添加一个与选择器下控制器视图大小相同的透明按钮。

显示选择器时设置button.hidden = NO,并在隐藏选择器时设置button.hidden = YES

有一些方法可以隐藏选择器。最简单的方法是设置picker.hidden = YES

答案 2 :(得分:-5)

如果您正在使用UIScrollView

a

将不会被调用,因为touchesBegan是UIView的方法,而不是UIScrollView的方法。