Question

我需要能够对可以包含多个值的列（下面）执行某些操作。＆＃39; HearAboutEvent＆＃39;列具有由逗号分隔的多个值。这些值中的每一个对应于另一个表中的条目。所以11273的价值将等于facebook，11274将意味着无线电，11275将意味着商业。

我正在使用的数据如下所示：

weather ID  MemberID    SubscriptionID  DateEntered     ParticipatedBefore  ParticipatedBeforeCities    WeatherDependent    NonRefundable   TShirtSize  HearAboutEvent
Yes     24      18          1           2013-12-19          0                   NULL                        10950           10952           10957       11273, 11274, 11275

我可以通过正确的联接来解决＆＃39;天气＆＃39;的值，注意它是第一列和第8列。

这是我迄今为止创建的用于解析WeatherDependent值的查询：

SELECT CFS1.Name as 'weather', *
FROM FSM_CustomForm_693 t
LEFT JOIN FSM_CustomFormSelectOptions CFS1 ON CFS1.ID = t.WeatherDependent 
where t.ID = 24

最终我需要让数据看起来像这样：

weather ID  MemberID    SubscriptionID  DateEntered     ParticipatedBefore  ParticipatedBeforeCities    WeatherDependent    NonRefundable   TShirtSize  HearAboutEvent
Yes     24      18          1           2013-12-19          0                   NULL                        10950           10952           10957       Facebook, radio, commercial

Answer 1

我认为您可以用来实现这一目标的是：

分裂TVF功能 - http://msdn.microsoft.com/en-us/library/ms186755.aspx
交叉申请 - http://technet.microsoft.com/en-us/library/ms175156.aspx
STUFF＆amp; FOR XML PATH - http://msdn.microsoft.com/en-us/library/ms188043.aspx＆amp; http://msdn.microsoft.com/en-us/library/ms190922.aspx

更进一步，你需要这样的东西：请原谅我对子查询的大量使用。

CREATE FUNCTION dbo.Split (@sep char(1), @s varchar(512))
RETURNS table
AS
RETURN (
    WITH Pieces(pn, start, stop) AS (
      SELECT 1, 1, CHARINDEX(@sep, @s)
      UNION ALL
      SELECT pn + 1, stop + 1, CHARINDEX(@sep, @s, stop + 1)
      FROM Pieces
      WHERE stop > 0
    )
    SELECT pn,
      SUBSTRING(@s, start, CASE WHEN stop > 0 THEN stop-start ELSE 512 END) AS s
    FROM Pieces
  )
GO

SELECT 
O.A,O.B,O.C,O.D,O.E,O.F,O.G,O.H,O.I,O.J,O.Stuffed
FROM (
    SELECT
    * 
    ,STUFF((
        SELECT ', ' + Name
        FROM (
            SELECT 
            V.*
            ,Y.Name
            FROM (
                SELECT 
                'Yes' AS A
                ,24 AS B
                ,18 AS C
                ,1 AS D
                ,'2013-12-19' AS E
                ,0 AS F
                ,NULL AS G
                ,10950 AS H
                ,10952 AS I
                ,10957 AS J
                ,'11273, 11274, 11275' AS K
            )
            AS V
            CROSS APPLY dbo.Split(',',REPLACE(K,' ','')) AS P
            JOIN (
                SELECT 11273 AS Id , 'Facebook' AS Name UNION ALL
                SELECT 11274 AS Id , 'radio' AS Name UNION ALL
                SELECT 11275 AS Id , 'commercial' AS Name
            )Y ON y.Id = p.s) ExampleTable
            FOR XML PATH('') 
            ), 1, 1, '' )
    AS [Stuffed]
    FROM (
        SELECT 
        V.*
        FROM (
            SELECT 
            'Yes' AS A
            ,24 AS B
            ,18 AS C
            ,1 AS D
            ,'2013-12-19' AS E
            ,0 AS F
            ,NULL AS G
            ,10950 AS H
            ,10952 AS I
            ,10957 AS J
            ,'11273, 11274, 11275' AS K
        )
        AS V
        CROSS APPLY dbo.Split(',',REPLACE(K,' ','')) AS P
        JOIN (
            SELECT 11273 AS Id , 'Facebook' AS Name UNION ALL
            SELECT 11274 AS Id , 'radio' AS Name UNION ALL
            SELECT 11275 AS Id , 'commercial' AS Name
        )Y ON y.Id = p.s
    )Z 
) O
GROUP BY O.A,O.B,O.C,O.D,O.E,O.F,O.G,O.H,O.I,O.J,O.K,O.Stuffed

然后拆分值将值解析为名称

1 个答案: