Question

我必须在bash脚本中运行一堆命令，我想回显当前正在运行的命令：

我有这个文件（约100行）：

nohup command1 param1 param2
nohup command2 p1 p2
nohup cmd3 p1 p2 param3

我想：

echo "Running command1" ; nohup command1 param1 param2
echo "Running command2" ; nohup command2 p1 p2
echo "Running cmd3" ; nohup cmd3 p1 p2 param3

我试过猛拉但是一次复制1行，有没有办法复制所有的行？

Answer 1

正则表达式是你需要的：

:%s/^\(nohup\) \([a-zA-Z0-9]*\)/echo "Running \2"; \1 \2/

Answer 2

您可以录制宏。

假设您在文件的第一个字符上，则应键入：

`qa`              "Start recording a macro into a
`w`               "move to first word following nohup
`yiw`             "copy the word under cursor
`^`               "move cursor back to beginning of line
`i`               " enter insert mode
`echo "Runnning<ESC>pi";<ESC>`  "paste the previously copied word
`j`               " go down one line
`^`               "move cursor back to beginning of line
`q`               " stop recording the macro
`@a`              " rexecute macro on second line

如果按预期方式工作，输入98@@应该会调用最后一次98次宏并格式化文件。

Answer 3

为什么不使用sh set -x？

来自bash（1）：

          -x      After expanding each simple command, for  command,  case
                  command, select command, or arithmetic for command, dis-
                  play the expanded value of PS4, followed by the  command
                  and its expanded arguments or associated word list.

复制多行和文本，直到VIM中的空格

3 个答案: