我正在开展一个春季项目,我发现这个奇怪的错误,找不到404
当我调用localhost时:8080 / BMS /我收到以下错误
No mapping found for HTTP request with URI [/BMS/$%7B] in DispatcherServlet with name 'spring'
请注意:我将一个Index.html文件作为webapp文件夹下的欢迎文件重定向到WEB-INF文件夹中的登录页面
所以我的问题是错误中的$%7B
是什么以及我如何解决这个问题?
的index.html
<head>
<meta http-equiv="refresh" content="0; url=http://localhost:8080/BMS/login.html" />
</head>
Web.xml中
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>BMS</display-name>
<filter>
<filter-name>encoding-filter</filter-name>
<filter-class>
org.springframework.web.filter.CharacterEncodingFilter
</filter-class>
<init-param>
<param-name>encoding</param-name>
<param-value>UTF-8</param-value>
</init-param>
<init-param>
<param-name>forceEncoding</param-name>
<param-value>true</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>encoding-filter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>default</servlet-name>
<servlet-class>
org.apache.catalina.servlets.DefaultServlet
</servlet-class>
<init-param>
<param-name>debug</param-name>
<param-value>0</param-value>
</init-param>
<init-param>
<param-name>listings</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/login.html</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>*.html</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
</web-app>
答案 0 :(得分:0)
根据网址编码,参考%7B
表示{
查看index.html的这一行
<meta http-equiv="refresh" content="0; url=http://localhost:8080/BMS/login.html" />
尝试在零&amp;之间删除空格网址。 将网址设为网址。
<meta http-equiv="refresh" content="0;URL=http://localhost:8080/BMS/login.html" />
希望这会对你有所帮助。