Question

我在REST应用程序中使用jaxb。我想通过Web表单发送XML文件。然后java类将解组InputStream。

private void unmarshal(Class<T> docClass, InputStream inputStream)
    throws JAXBException {
    String packageName = docClass.getPackage().getName();
    JAXBContext context = JAXBContext.newInstance(packageName);
    Unmarshaller unmarshaller = context.createUnmarshaller();
    Object marshaledObject = unmarshaller.unmarshal(inputStream);
}

触发unmarshal方法的jsp-File有form，如下所示：

<form action="#" method="POST">
    <label for="id">File</label>
    <input name="file" type="file" />
    <input type="submit" value="Submit" />
</form>

我得到以下ParserException：

javax.xml.bind.UnmarshalException - with linked exception: [org.xml.sax.SAXParseException: Content is not allowed in prolog.]。

一般here回答了这个问题，但我确信我的文件没有损坏。当我使用相同的文件从java-Class中调用代码时，不会抛出异常。

// causes no exception
File file = new File("MyFile.xml");
FileInputStream fis = new FileInputStream(file);
ImportFactory importFactory = ImportFactory.getInstance();
importFactory.setMyFile(fis);

// but when i pass the file with a web form
@POST
@Produces(MediaType.TEXT_HTML)
@Consumes(MediaType.APPLICATION_FORM_URLENCODED)
public Response create(@FormParam("file") InputStream filestream) {
    Response response;

    // is a BufferedInputStream, btw    
    LOG.debug("file is type: " + filestream.getClass().getName());

    try { 
        ImportFactory importFactory = ImportFactory.getInstance();
        importFactory.setMyFile(filestream);

        Viewable viewable = new Viewable("/sucess", null);
        ResponseBuilder responseBuilder = Response.ok(viewable);
        response = responseBuilder.build();

    } catch (Exception e) {
        LOG.error(e.getMessage(), e);
        ErrorBean errorBean = new ErrorBean(e);
        Viewable viewable = new Viewable("/error", errorBean);
        ResponseBuilder responseBuilder = Response.ok(viewable);
        response = responseBuilder.build();
    }
    return response;
}

Answer 1

@FormParam（“file”）的内容InputStream文件流是file = MyFile.xml而不是它的内容。

Answer 2

XML标题是否与下面的标题类似？

<?xml version='1.0' encoding='utf-8'?>

Answer 3

确认验证操作后验证器中使用的InputStream是重置。没有重置它你可以得到许多奇怪的例外。

我希望它会有所帮助：）

使用泽西时的XML文件进行发布时出现SAXParseException

3 个答案: