Question

这张桌子叫做学校。它有两列名为students和teachers。我想在各栏目中添加教师和学生姓名。这是我的xml

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="school.xsl"?>
<school>
    <students>
        <student>
            <name>Lakshman</name>
        </student>
        <student>
            <name>Tharindu</name>
        </student>
    </students>
    <teachers>
        <teacher>
            <name>Sarath</name>
        </teacher>
        <teacher>
            <name>Hemantha</name>
        </teacher>
        <teacher>
            <name>Upali</name>
        </teacher>
    </teachers>
</school>

这是xml文件引用的xsl文件

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:template match="/">
        <html>
            <body>
                <h2>School</h2>
                <table border="1">
                    <tr bgcolor="#9acd32">
                        <th>Students</th>
                        <th>Teachers</th>
                    </tr>
                    <td>
                       <xsl:for-each select="school/students/student">
                           <tr><td><xsl:value-of select="name"/></td></tr>
                       </xsl:for-each>
                    </td>
                    <td>
                        <xsl:for-each select="school/teachers/teacher">
                            <tr><td><xsl:value-of select="name"/></td></tr>
                        </xsl:for-each>
                    </td>
                </table>
            </body>
        </html>
    </xsl:template>
</xsl:stylesheet>

但它会像这样打印表格。

enter image description here

无论如何都要将学生和教师的名字添加到他们各自的栏目中？

Answer 1

使用

<xsl:stylesheet version="1.0"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:variable name="students" select="school/students/student"/>
    <xsl:variable name="teachers" select="school/teachers/teacher"/>

    <xsl:template match="/">

        <html>
            <body>
                <h2>School</h2>
                <table border="1">
                    <tr bgcolor="#9acd32">
                        <th>Students</th>
                        <th>Teachers</th>
                    </tr>
                    <xsl:apply-templates select="$students"/>
                    <xsl:variable name="stud-count" select="count($students)"/>
                    <xsl:apply-templates select="$teachers[position() > $stud-count]"/>
                </table>

            </body>
        </html>
    </xsl:template>

    <xsl:template match="student">
      <xsl:variable name="pos" select="position()"/>
      <tr>
        <td><xsl:value-of select="name"/></td>
        <td><xsl:value-of select="$teachers[$pos]/name"/></td>
      </tr>
   </xsl:template>

   <xsl:template match="teacher">
     <tr>
       <td>&#160;</td>
       <td>
         <xsl:value-of select="name"/>
       </td>
     </tr>
  </xsl:template>
</xsl:stylesheet>

如何在xslt中以列方式添加数据HTML表

1 个答案: