Question

我在屏幕中间画了一块8x8格子板，假设板周围是空的空间，但在每一行和一列的末尾看起来它继续画到屏幕的边缘。有什么可以解决这个问题，还是我必须在电路板周围创建另一个表面？

注意：我认为问题出在drawMainBoard函数的某个地方。我尝试创建一个行，每个框开始和结束，行停在应该的位置，但是电路板继续绘制到屏幕的边缘。

import pygame._view
import pygame
import sys
from pygame.locals import*
import time
import random

FPS=30
fpsClock=pygame.time.Clock()

displayWidth=600
displayHeight=600

Xmargin=(displayWidth/12)*2
Ymargin=(displayHeight/12)*2

boardRows=8
boardColumns=8

boxx=(displayWidth-(Xmargin*2))/8
boxy=(displayHeight-(Ymargin*2))/8



DISPLAYSURF=pygame.display.set_mode((displayWidth,displayHeight),0,32)

colorRed=   (255,0,0)
colorBlack= (0,0,0)
colorWhite= (255,255,255)
colorRed2=  (150,0,0)
colorBlack2=(10,10,10)

pygame.init()

myFont=pygame.font.SysFont("ariel",15)

def mainscreen():
    DISPLAYSURF.fill((255,255,255))

    drawMainboard()

    for event in pygame.event.get():
        if event.type==QUIT:
            pygame.quit()
            sys.exit()

    pygame.display.update()

    fpsClock.tick(FPS)

def drawBox(boxstart,boxend,boxcolor):
    pygame.draw.rect(DISPLAYSURF,boxcolor,(boxstart,boxend),0)






def drawMainboard():
    firstColor=colorBlack
    boxxstart=Xmargin
    boxystart=Ymargin
    boxxend=Xmargin+boxx
    boxyend=Ymargin+boxy
    lettercount=0

    boxstart=(boxxstart,boxystart)
    boxend=(boxxend,boxyend)
    for columns in range(0,boardColumns):
        if firstColor==colorRed:
            firstColor=colorBlack
        else:
            firstColor=colorRed
        for rows in range(0,boardRows):
            drawBox(boxstart,boxend,firstColor)
            label=myFont.render(str(lettercount),20,(0,0,255))
            DISPLAYSURF.blit(label,(boxxstart,boxystart))
            pygame.draw.line(DISPLAYSURF,colorWhite,(boxxend,boxyend),(boxxstart,boxystart),1)
            lettercount+=1
            if firstColor==colorRed:
                firstColor=colorBlack
            else:
                firstColor=colorRed

            boxxstart+=boxx
            boxxend+=boxx
            boxstart=(boxxstart,boxystart)
            boxend=((boxxend),(boxyend))
        boxxstart=Xmargin
        boxxend=Xmargin+boxx
        boxystart+=boxy
        boxyend+=boxy
        boxstart=(boxxstart,boxystart)
        boxend=(boxxend,boxyend)


while True:
    mainscreen()

Answer 1

问题出在您的drawBox功能范围内。您传递参数boxstart和boxend，它们代表要绘制的矩形的左上角和右下角。

但是pygame.draw.rect函数需要一个Rect类似的对象或元组，表示矩形左上角的x和y坐标，它的大小。因此，当您传递值(450, 100), (500, 150)时，您不会从Rect到(450, 100)绘制(500, 150)，而是从(450, 100)开始绘制一个长度的矩形500，高150.

一个简单的解决方法是在函数中计算正确的大小：

def drawBox(boxstart,boxend,boxcolor):
    sx, sy = boxstart
    ex, ey = boxend
    r = Rect(sx, sy, ex-sx, ey-sy)
    pygame.draw.rect(DISPLAYSURF,boxcolor,r,0)

或简单地使用Rect类：

from itertools import cycle

...

def drawMainboard():
    # the current rect we're going to draw
    current = Rect((Xmargin, Ymargin), (boxx, boxy))

    # the colors we use
    colors = cycle((pygame.color.Color('Black'), pygame.color.Color('Red')))

    lettercount = 0
    for _ in range(0, boardRows):
        # switch colors on each row, so the last rect on a row
        # has the same color as the starting rect on the next row
        # only need on an even number of columns
        next(colors)
        for _ in range(0, boardColumns):
            # switch color and draw rect
            pygame.draw.rect(DISPLAYSURF, next(colors), current, 0)
            # draw label. We can simply use 'current' as position
            label=myFont.render(str(lettercount),20,(0,0,255))
            DISPLAYSURF.blit(label, current)
            # draw the line. We can simply use current.topleft, current.bottomright
            pygame.draw.line(DISPLAYSURF,colorWhite, current.topleft, current.bottomright, 1)
            lettercount += 1
            # move the current rect to the next column
            current.move_ip((boxx, 0))
        # for the next row, start at 'Xmargin' and move the rect down one row
        current.topleft = Xmargin, current.top + boxy

Pygame：画一个方格板，继续画在盒子的尽头

1 个答案: