Question

如果我有以下代码：

class A_Interface {
 public:
    virtual void i_am_a() = 0;
};

class A : public A_Interface {
 public:
    void i_am_a() {printf("This is A\n");}
};

class B_interface {
 public:
    virtual void i_am_b() = 0;
    // would like to run i_am_a()
};
class B : public A, public B_interface {
 public:
    void i_am_b() {printf("This is B\n");}
};

int main() {
    B BO;
    B_interface* BI = &BO;

    BI->i_am_b();
    // ******* WOULD LIKE TO RUN THE FOLLOWING ********
    BI->i_am_a();
}

有什么选择能够从B_Interface指针运行A类成员函数？

我知道B_interface可以将A_interface继承为：

class B_Interface：virtual public A_interface ...

class A : virtural public A_Interface ...

但是这使我无法根据自己的知识使用GMOCK来模拟B课。我有什么选择？

...谢谢

Answer 1

内部class B_interface有：

void i_am_a()
{
     // throws if the object does not actually have A as a base
     dynamic_cast<A &>(*this).i_am_a();
}

Answer 2

好的，我错了，再说:(。所以答案代码可以是这样的：

class A_Interface {
 public:
    virtual void i_am_a() = 0;
};

class A : virtual public A_Interface {
 public:
    void i_am_a() {printf("This is A\n");}
};

class B_Interface : virtual public A_Interface {
 public:
    virtual void i_am_b() = 0;
    // would like to run i_am_a()
};

class B : public A, public B_interface {
 public:
    void i_am_b() {printf("This is B\n");}
};

GMock可以是这样的：

class MockB : public B_Interface, public MockA {
    MOCK_METHOD0(foo, int(int));
}

这在实际应用中对我有用，但看起来有点乱。

类接口功能

2 个答案: