我正在尝试将数据库中包含的user_id传递给单击按钮时显示在Bootstrap模式中的表单。
按钮:
<td id="fired">
<button class="btn btn-default btn-danger btn-xs fired" data-id="<?php echo $row['user_id']; ?>">
Fired
</button>
</td>
JQuery的:
$(document).ready(function(){
$(".fired").click(function(){
$("#user_id").val($(this).attr('data-id'));
$('#firedModal').modal('show');
});
});
模态:
<div class="modal fade" id="firedModal" tabindex="-1" role="dialog" aria-labelledby="firedModal" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal"><span aria-hidden="true">×</span><span class="sr-only">Close</span></button>
<h4 class="modal-title" id="firedModal">Fire Habbo</h4>
</div>
<form class="form-signin" role="form" action="" method="post">
<div class="modal-body">
<input type="text" class="form-control" placeholder="Firing Reason" name="fired_reason" required autofocus />
<input type="text" class="form-control" placeholder="Firing Tag" name="fired_tag" required />
<input type="text" class="form-control" placeholder="Date" name="fired_date" required />
<input type="text" class="form-control" placeholder="Status (MAY JOIN AS RECRUIT/PARDONED/NEVER REHIRE)" name="fired_status" />
<input type="hidden" class="form-control" name="user_id" value="" />
</div>
<div class="modal-footer">
<button type="submit" class="btn btn-primary">Fire</button>
</div>
<button type="button" class="btn btn-default" data-dismiss="modal">
Close
</button>
</form>
</div>
</div>
</div>
但是,单击按钮时,模式会显示,但user_id输入的值不会被行的user_id填充。我究竟做错了什么?感谢。
答案 0 :(得分:3)
使用此代码修改您的代码。
<input type="hidden" class="form-control" id="user_id" name="user_id" value="" />
$(document).ready(function(){
$("#fired").click(function(){
$("#user_id").val($(this).attr('data-id'));
$('#firedModal').modal('show');
});
});