Question

echo "Enter a grade"
read grade
if test $grade="A"
then
  basic=6000
elif test $grade="B"
then
  basic=5000
else
  basic=4000
fi
echo "Your basic is $basic"

当我在任何等级的终端中执行此代码时，它总是返回“你的基本是6000”。这段代码中的错误是什么？

Answer 1

#!/bin/bash
echo "Enter a grade"
# Read single char
read -n 1 grade
echo $grade
if [ "$grade" == 'A' ]; then
    basic=6000
elif [ "$grade" == 'B' ]; then
    basic=5000
else
    basic=4000
fi
echo "Your basic is $basic"

Answer 2

你需要在=。

周围加一个空格

就像现在一样，你只需给测试命令一个参数，即$ grade =“A”，因为空格分隔了参数。如果在=附近放置空格，那么test将有3个参数，即（扩展的）$ grade，=和“A”。

因此：

echo "Enter a grade"
read grade
if test $grade = "A"
then
  basic=6000
elif test $grade = "B"
then
  basic=5000
else
  basic=4000
fi
echo "Your basic is $basic"

如何在linux中使用if条件

2 个答案: