Question

我的json文件如下：

var obj = {
 Dilse : {"name":"Dil Se Re","length":"5:40","songType":"Romantic"},
 Dilse : {"name":"Jiya Jale","length":"3:50","songType":"Self Description"},
 Dilse : {"name":"Chaiyya Chaiyya","length":"4:30","songType":"Masti"},

 Rockstar : {"name":"Sadda haq","length":"5:40","songType":"Romantic"},
 Rockstar : {"name":"Tum ho Pas Mere","length":"3:50","songType":"Self Description"},
 Rockstar : {"name":"Sheher me","length":"4:30","songType":"Masti"},
}

我想在点击Dil se时检索Dilse条目，并在点击Rockstar时检索Rockstar条目。我已经在我的页面上有Dilse和Rockstar条目。

JS函数看起来像：

function dilSe(){

            document.getElementById("div0").innerHTML = ""; var k =0;
            if(xhr.readyState==4){
            if(xhr.status==200){
                var data=xhr.responseText;
                var arr=eval(data);
                for(var i=0;i<3;i++){             //I dont know if I should itearte like this !?

                            var link=document.createElement('a');
                            link.id='name1'+k++;
                            link.innerHTML="Song Name: " +obj.Dilse.name+"<br/>"+"Song Length: "+obj.Dilse.length+"<br/>"+"Song Type: "+obj.Dilse.songType+"<br/><br/>";
                            console.log("link.id is "+link.id);
                            link.setAttribute('href','#');

                            link.addEventListener('click',albums[link.id]);

                            div0.appendChild(link);
                            } 
                }else{
                    div0.innerHTML="Oops, error in communication!";
                    div0.style.color="red";
                }
            }
}


function rockStar(){

            document.getElementById("div0").innerHTML = ""; var k =0; var r=3;
            if(xhr.readyState==4){
            if(xhr.status==200){
                var data=xhr.responseText;
                var arr=eval(data);
                for(var i=0;i<3;i++){       //I dont know if I should itearte like this !?

                            var link=document.createElement('a');
                            link.id='name2'+k++;
                            link.innerHTML="Song Name: " +obj.Rockstar.name+"<br/>"+"Song Length: "+obj.Rockstar.length+"<br/>"+"Song Type: "+obj.Rockstar.songType+"<br/><br/>";
                            console.log("link.id is "+link.id);
                            link.setAttribute('href','#');
                            console.log("obj.rockstar.name is "+obj.Rockstar.name);
                            link.addEventListener('click',albums[link.id]);

                            div0.appendChild(link);
                            } 
                }else{
                    div0.innerHTML="Oops, error in communication!";
                    div0.style.color="red";
                }
            }
}

但最后我得到的是Dilse的最后一个条目（即Chaiyya Chaiyya）和Rockstar的最后一个条目（即Sheher me）。我想要显示所有三个条目。

Answer 1

您的JSON对象不正确。你显然不能拥有相同键的多个条目（你正在做的是告诉JS：＆＃34;詹姆斯是这个人。啊不，詹姆斯是另一个人。啊不再，詹姆斯是第三个人＆＃34;。当然，他只记得最后一个。

您需要使用数组。最简单的解决方案是将您的JSON修改为如下所示：

var obj = {
 Dilse :
 [
    {"name":"Dil Se Re","length":"5:40","songType":"Romantic"},
    {"name":"Jiya Jale","length":"3:50","songType":"Self Description"},
    {"name":"Chaiyya Chaiyya","length":"4:30","songType":"Masti"},
 ],

 Rockstar :
 [
    {"name":"Sadda haq","length":"5:40","songType":"Romantic"},
    {"name":"Tum ho Pas Mere","length":"3:50","songType":"Self Description"},
    {"name":"Sheher me","length":"4:30","songType":"Masti"},
 ],
}

还有其他可能的选项，例如单个数组（非关联），以及作为每个对象内部值之一的键，但这需要您遍历整个数组以查找所需的内容

仅通过ID显示最后一个条目的JSON文件是不同的

1 个答案: