我使用BroadcastReceiver来了解耳机是否插在设备上,但是"状态"意图额外立即返回1(插入)在每种情况下。
这是我的代码:
public class Class {
boolean isHeadsetOn;
IntentFilter headsetReceiverFilter;
HeadsetPluggedReceiver headsetReceiver;
public Class(Context context) {
this.headsetReceiverFilter = new IntentFilter(Intent.ACTION_HEADSET_PLUG);
this.headsetReceiver = new HeadsetPluggedReceiver();
context.registerReceiver(this.headsetReceiver, this.headsetReceiverFilter);
}
private class HeadsetPluggedReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
switch(intent.getIntExtra("state", -1)) {
case 0:
Synthesizer.this.isHeadsetOn = false;
Log.d("onreceive", "off");
case 1:
Synthesizer.this.isHeadsetOn = true;
Log.d("onreceive", "on");
default:
// shit
}
}
}
}
这是我的日志:
// not plugged. plugging in
onreceive | on
// unplugging
onreceive | off
onreceive | on
// plugging in again
onreceive | on
// plugging off again
onreceive | off
onreceive | on
我该如何解决这个问题?
提前谢谢。
答案 0 :(得分:1)
**应该是:**
@Override
public void onReceive(Context context, Intent intent) {
switch(intent.getIntExtra("state", -1)) {
case 0:
Synthesizer.this.isHeadsetOn = false;
Log.d("onreceive", "off");
break; //<---------
case 1:
Synthesizer.this.isHeadsetOn = true;
Log.d("onreceive", "on");
break; //<---------
default:
// shit
}
}
}
答案 1 :(得分:0)
您的交换机案例中需要使用break语句。现在你的逻辑正在落到案例1。