Question

嘿，我是HTML和PHP的新手，我已经成功完成了我想要实现的目标，但有一件事情出错了：案例是：请记住，这不是作业，但我正在努力学习！

我有一个mytable.php文件，我必须将记录显示到从mysql db获取的表中

然后我有一个编辑按钮，以便我可以编辑我的详细信息

按编辑按钮我转到edit.php，我必须在mysqli查询中编辑记录数据，其中某些条件应来自mytable.php 我的代码是：

\ mytable.php //

session_start();
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Q4Part a</title>
</head>

<body>


    //and for mysqli_connection string will be
        $con=mysqli_connect('localhost','root','','db');
            if($con){
                $result=mysqli_query($con,"select * from users");
                    if($result){
                        echo "<table>";

                        echo "<tr>";
                            echo "<td>";
                                echo "Username";
                            echo "</td>";

                                echo "<td>";
                                    echo "Password";
                                echo "</td>";

                                    /*echo "<td>";
                                        echo "Pass";
                                    echo "</td>";

                                        echo "<td>";
                                            echo "Phone";
                                        echo "</td>";

                                            echo "<td>";
                                                echo "Address";
                                            echo "</td>";

                                                echo "<td>";
                                                    echo "Action";
                                                echo "</td>";   */
                        echo "</tr>";
                            while($row=mysqli_fetch_array($result)){
                                echo "<tr>";
                                    echo "<td>";
                                        echo $row['myusername'];
                                    echo "</td>";

                                        echo "<td>";
                                            echo $row['mypassword'];
                                        echo "</td>";
                                        echo "<td>";
                                                            echo "<a href='edit.php'>edit</a>";

                                                            $_SESSION['username']=$row['myusername'];
                                                            //to go to the edit.php
                                                        echo "</td>";

                            echo "</tr>";
                            }
                        echo "</table>";
                    }else{
                        echo mysqli_error($con);
                        //so that if query won't run!
                    }
            }
            else{
                echo mysqli_connect_error($con);
                //or you can use exit that shows an error message and terminates the current script
                //and or die which is a substitue for exit function and also shows the error message and terminates the current script
                //so
                exit("Connection error!");
                    //we can also use die(string);
                die("Connection error");
            }

</body>
</html>

\ edit.php //

    session_start();
    $username=$_SESSION['username'];
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Edit File</title>
</head>

<body>
    <?php
        $con=mysqli_connect('localhost','root','','db');
            if($con){
                $result=mysqli_query($con,"select * from users where myusername='".$username."'");
                //where $username contains the current user that has been already signed in in the current time!//
                    if($result){
                        echo "<form action='save_edit.php' method='post'>";
                        echo "<table>";
                            echo "<th colspan='5'>";
                                echo "edit your details!";
                            echo "</th>";

                        while($row=mysqli_fetch_array($result)){
                            echo "<tr>";
                                echo "<td>";
                                    echo "<input type='text' name='username' value='".$row['myusername']."'>";
                                echo "</td>";

                                echo "<td>";
                                    echo "<input type='text' name='email' value='".$row['mypassword']."'>";
                                echo "</td>";



                                echo "<td>";
                                    echo "<button type='submit'>Edit Changes</button>";
                                echo "</td>";
                            echo "</tr>";
                        }
                        echo "</table>";

                        echo "</form>";

                    }else{
                        echo mysqli_error($con);
                    }
            }
            else{
                echo mysqli_connect_error($con);    
            }
    ?>
</body>
</html>

所有工作都很好，但只有当我点击“编辑”链接时才会得到最后的结果

Answer 1

尝试使用mysqli_fetch_assoc（）而不是mysqli_fetch_array（）。您正在使用散列图（关联数组），因此请确保相应地访问它。尝试在while语句后执行var_dump($row);以从阵列中打印对象。

最后，您绝不应将密码以纯文本形式存储在数据库中。密码应存储为哈希值，因此您永远无法再次查看密码。当用户登录时，通过重新散列并比较匹配来检查传递是否有效。例如：$ pass = md5($_POST['password'])

您还应该考虑使用HTML5。您的doctype使您使用HTML4，并没有太多理由再这样做了。我建议更改为HTML5设置。

Answer 2

$_SESSION['username']将存储您从数据库/页面上显示的最后一个用户名，因此无法正常工作。

执行此操作的标准方法是为数据库中的每一行使用唯一标识符，并将其作为URL参数传递给edit.php。

如果用户名始终是唯一的，您可以执行以下操作。

在mytable.php中：

//echo "<a href='edit.php'>edit</a>";
echo "<a href='edit.php?username=" . urlencode($row['myusername']) . "'>edit</a>";
//$_SESSION['username']=$row['myusername'];

在edit.php中：

//$username=$_SESSION['username'];
$username = $_GET['username'];

从HTML表中获取值并使用它来编辑记录

2 个答案: