struts datagrid问题 - 无法解决这个问题

时间:2010-03-17 02:57:06

标签: datagrid struts

我正在使用struts-layout创建datagrid。我遇到了这个问题

javax.servlet.ServletException:DispatchMapping [/ monitor / datagridBL]でハンドラプロパティが定义されていません     at org.apache.struts.actions.DispatchAction.getParameter(DispatchAction.java:325)     在org.apache.struts.actions.DispatchAction.execute(DispatchAction.java:170)     at org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:431)     在org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:236)     在jp.terasoluna.fw.web.struts.action.RequestProcessorEx.process(RequestProcessorEx.java:149)     在org.apache.struts.action.ActionServlet.process(ActionServlet.java:1196)     在org.apache.struts.action.ActionServlet.doGet(ActionServlet.java:414)     在javax.servlet.http.HttpServlet.service(HttpServlet.java:707)     在javax.servlet.http.HttpServlet.service(HttpServlet.java:820)     在weblogic.servlet.internal.StubSecurityHelper $ ServletServiceAction.run(StubSecurityHelper.java:227)     在weblogic.servlet.internal.StubSecurityHelper.invokeServlet(StubSecurityHelper.java:125)     在weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:292)     在weblogic.servlet.internal.TailFilter.doFilter(TailFilter.java:26)     在weblogic.servlet.internal.FilterChainImpl.doFilter(FilterChainImpl.java:56)     在jp.co.anicom.fw.web.common.controller.RequestEncodeFilter.doFilter(RequestEncodeFilter.java:42)     在weblogic.servlet.internal.FilterChainImpl.doFilter(FilterChainImpl.java:56)     在jp.co.anicom.fw.web.common.controller.SessionExpirationFilter.doFilter(SessionExpirationFilter.java:89)     在weblogic.servlet.internal.FilterChainImpl.doFilter(FilterChainImpl.java:56)     at weblogic.servlet.internal.WebAppServletContext $ ServletInvocationAction.run(WebAppServletContext.java:3588)     在weblogic.security.acl.internal.AuthenticatedSubject.doAs(AuthenticatedSubject.java:321)     在weblogic.security.service.SecurityManager.runAs(SecurityManager.java:121)     在weblogic.servlet.internal.WebAppServletContext.securedExecute(WebAppServletContext.java:2200)     在weblogic.servlet.internal.WebAppServletContext.execute(WebAppServletContext.java:2106)     在weblogic.servlet.internal.ServletRequestImpl.run(ServletRequestImpl.java:1428)     在weblogic.work.ExecuteThread.execute(ExecuteThread.java:201)     在weblogic.work.ExecuteThread.run(ExecuteThread.java:173)

我一直在寻找解决方法。有人会帮我吗...

1 个答案:

答案 0 :(得分:0)

检查struts-config文件中是否存在您的操作文件(type = xxx)。如果还定义了“action”,请检查您的操作中是否存在具有相同名称的方法。如果参数已定义但参数中不存在,则必须在操作中创建“未指定”方法。如果您不在struts-config文件中使用“parameter”,请使用“execute”方法。

///////////////////

例如在strust配置中定义的参数:

url:yoursite.com/mypage/myaction.html?method=test

<action
  path="/mypage/myaction"
  type="myfolder.action.MyAction"
  name="MyActionForm"
  validate="false"
  parameter="method"
  scope="request">
  <forward name="success" path="/view/yourfile.jsp"/>
</action>



public class MyAction{


 public ActionForward test (ActionMapping mapping,
         ActionForm actform,
         HttpServletRequest request,
         HttpServletResponse response) throws Exception { 

                 ...

  return mapping.findForward("success");

 }


}

//////////////////

例如,在trusts config中没有定义参数:

url:yoursite.com/mypage/myaction.html

<action 
  path="/mypage/myaction"
  type="myfolder.action.MyAction"
  name="MyActionForm"
  validate="false"
  scope="request">
  <forward name="success" path="/view/yourpage.jsp"/>
</action>


public class MyAction {


 public ActionForward execute (ActionMapping mapping,
         ActionForm actform,
         HttpServletRequest request,
         HttpServletResponse response) throws Exception { 

                 ...

  return mapping.findForward("success");

 }


}

我的解释清楚了吗? :-) 不明点御座いましたら,远虑なくきいて下さい〜

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