Swift - 如何将视图控制器的引用传递给子UIView类?

时间:2014-07-06 09:00:51

标签: ios uiview uiviewcontroller swift

我有一个UIViewController和一个UIView。当我尝试在UIView中添加警报时,我必须使用控制器来呈现UIAlertController。如何将UIViewController的引用传递给UIView类?或者,我如何创建控制器的委托?

class GameViewController: UIViewController {
    @IBOutlet var gameBoardUIView: GameBoardUIView
    ...
}

class GameBoardUIView: UIView {
    ...
    func move() {
        if !gameBoard.checkNextMoveExist() {
            var alert = UIAlertController(title: "Game Over", message: nil, preferredStyle: UIAlertControllerStyle.Alert)
            alert.addAction(UIAlertAction(title: "Ok", style: UIAlertActionStyle.Cancel, handler: {(action: UIAlertAction!) in
                println("Game Over")
            }))
            }))
            // Following would fail because self is not a UIViewController here
            // self.presentViewController(alert, animated: true, completion: nil)
        }
    }
}

2 个答案:

答案 0 :(得分:17)

遵循MVC模式,ViewController知道它的视图,但View不应该知道ViewController。相反,您应该声明GameBoardUIView采用的ViewController委托协议,如下所示:

// Delegate protocol declared here
protocol GameBoardUIViewDelegate: class {
    func checkIfNextMoveExistsForGameBoardUIView(gameBoardUIView: GameBoardUIView)
}

class GameBoardUIView: UIView {

    // GameBoardUIView has a delegate property that conforms to the protocol
    // weak to prevent retain cycles
    weak var delegate:GameBoardUIViewDelegate?

    func move() {
        if !gameBoard.checkNextMoveExist() {
            delegate?.checkIfNextMoveExistsForGameBoardUIView(gameBoardUIView: self)
        }
    }

}

// View controller subclass adopts the protocol
class GameViewController: UIViewController, GameBoardUIViewDelegate {

    @IBOutlet var gameBoardUIView: GameBoardUIView!

    override func viewDidLoad() {
        super.viewDidLoad()
        gameBoardUIView.delegate = self
    }

    // Delegte protocol method
    func checkIfNextMoveExistsForGameBoardUIView(gameBoardUIView: GameBoardUIView) {

        let alert = UIAlertController(title: "Game Over", message: nil, preferredStyle: .alert)

        alert.addAction(UIAlertAction(title: "Ok", style: .cancel, handler: {(action: UIAlertAction!) in
            print("Game Over")
        }))

        // If you need to feed back to the game view you can do it in the completion block here
        present(alert, animated: true, completion: nil)
    }
}

答案 1 :(得分:0)

或者,您也可以从.xib发布通知并让父视图控制器观察它。您可以在发布期间通过userInfo对象发送数据。