Question

我有这段代码：

...
request data = new request(); 
data.username = formNick; 
xml = data.Serialize();
...

[System.Serializable] 
public class request 
{ 
   public string username; 
   public string password;

   static XmlSerializer serializer = new XmlSerializer(typeof(request));
   public string Serialize() 
   { 
      StringBuilder builder = new StringBuilder(); 
      XmlWriterSettings settings = new XmlWriterSettings();
settings.OmitXmlDeclaration = true;
settings.Encoding = Encoding.UTF8;
      serializer.Serialize(
         System.Xml.XmlWriter.Create(builder, settings ), 
         this); 

      return builder.ToString(); 
   } 
   public static request Deserialize(string serializedData) 
   { 
      return serializer.Deserialize(new StringReader(serializedData)) as request; 
   } 
}

我想为某些节点添加属性并创建一些子节点。另外如何解析xml如下：

<answer>
  <player id="2">
    <coordinate axis="x"></coordinate>
    <coordinate axis="y"></coordinate>
    <coordinate axis="z"></coordinate>
    <action name="nothing"></action>
  </player>
  <player id="3">
    <coordinate axis="x"></coordinate>
    <coordinate axis="y"></coordinate>
    <coordinate axis="z"></coordinate>
    <action name="boom">
      <1>1</1>
      <2>2</2>
    </action>
  </player>
</answer>

它不是XML文件，它是来自HTTP服务器的答案。

Answer 1

如果您有一个XSD文件描述您将从服务器接收的XML，那将是最好的。然后，您可以使用XSD.EXE程序生成具有适当.NET属性的.NET类。然后，您可以使用XmlSerializer.Deserialize。

我打算亲自为你创建这样一堂课。这将是一次快速尝试，可能是错误的（我必须重新开始工作！）

试试这个，看它是否有效。

using System.Collections.Generic;
using System.Xml;
using System.Xml.Serialization;


[XmlRoot("answer")]
public class Answer
{
    [XmlElement]
    public List<Player> Players { get; set; }
}

public class Player
{
    [XmlAttribute("id")]
    public int ID { get; set; }

    [XmlElement]
    public List<Coordinate> Coordinates { get; set; }

    [XmlElement("action")]
    public PlayerAction Action { get; set; }
}

public class PlayerAction
{
    [XmlAttribute("name")]
    public string Name { get; set; }

    [XmlAnyElement]
    public XmlElement[] ActionContents { get; set; }
}

public enum Axis
{
    [XmlEnum("x")]
    X,
    [XmlEnum("y")]
    Y,
    [XmlEnum("z")]
    Z
}

public class Coordinate
{
    [XmlAttribute("axis")]
    public Axis Axis { get; set; }

    [XmlText]
    public double Value { get; set; }
}

如何序列化为包含属性的XML？

1 个答案: