Question

import java.util.Scanner;

public class JavaMovies {
      Scanner det = new Scanner(System.in);
      int age = det.nextInt();

public static void main(String[] args){
    calculator();


}


public static void calculator(){

Scanner det = new Scanner(System.in);

    String rMovie = "Attack of the nerds";
    String mMovie = "Nerd lyfe";
    String pgMovie = "Nerd adventures";
    String gMovie = "Nerd playtime";
    System.out.println("These are the movies that are playing this weekend"
            + rMovie
            + mMovie
            + pgMovie
            + gMovie);
    System.out.println("Please input your age");
   int age = det.nextInt();


System.out.print("Input the movie you wish to see:");
    String x = det.nextLine();                             //Program ends here...

    if(x.equals("Attack of the nerds") & age > 17){
        System.out.println("You can see Attack of the nerds");

    }else if(x.equals("Attack of the nerds") & age < 18){
        System.out.println("You can see attack of the nerds!");

    }if(x.equals("Nerd lyfe")& age > 15){
        System.out.println("You can see Nerd lyfe");

    }else if(x.equals("Nerd lyfe")& age < 16){
        System.out.println("You can not see Nerd lyfe");

    }if (x.equals("Nerd adventures")& age > 10){
        System.out.println("You can see Nerd adventures");

    }else if(x.equals("Nerd adventures")& age < 11){
        System.out.println("You can not see Nerd adventures");

    }if(x.equals("Nerd playtime")& age > 5){
        System.out.println("You can see Nerd playtime");

    }else if(x.equals("Nerd playtime")& age < 6){
        System.out.println("You can not see Nerd playtime");


    }
}
}

在if语句的开头，一切都没问题，我该怎么做才能解决这个问题？

控制台输出（使用netbeans）跑：这些是本周末正在播放的电影攻击者书呆子游戏Nerd冒险游戏时间请输入您的年龄 14 输入您想看的电影：BUILD SUCCESSFUL（总时间：4秒）

Answer 1

我认为问题在于nextInt并没有用完整条线。如果您在提示年龄时键入32，nextInt将使用3和2字符，但仍有换行符字符在输入字符串中。然后，当您拨打nextLine时，效果是返回当前行中剩余的所有内容，直到下一个换行符。由于当前行仍有换行符，因此会String x = det.nextLine()将x设置为空字符串。

在提示观看电影之前尝试det.nextLine();。（您不需要将其分配给变量;只需抛弃结果。）这将导致扫描程序使用换行符，以便下一个nextLine()将获得另一行输入。

它到达if语句并停止工作，我做错了什么（java新手）

1 个答案: