我有这个专业档案
QT += qml quick widgets
TARGET = sPassKeeper
include(src/src.pri)
include(qml/qml.pri)
RESOURCES += \
resources.qrc
在src pri和qml pri中只有单行 qml.pri
OTHER_FILES += \
qml/main.qml
src.pri
SOURCES += \
src/main.cpp
在main.cpp中得到了这段代码
#include <QApplication>
#include <QQmlApplicationEngine>
#include <QtDebug>
int main(int argc, char *argv[])
{
QApplication app(argc, argv);
QQmlApplicationEngine engine(QUrl("qrc:/new/prefix1/qml/main.qml"));
qDebug() << "Ok engine created";
// Q_UNUSED(engine)
return app.exec();
}
main.qml
import QtQuick 2.0
import QtQuick.Controls 1.1
ApplicationWindow{
title: "sPassKeeper"
Button{
text: "Hello"
}
}
结果得到了这个输出
启用QML调试。只能在安全的环境中使用它。好 引擎创建
未显示任何内容且未完成处理。
答案 0 :(得分:7)
你错过了这个:
ApplicationWindow {
visible: true
Qt Creator的新项目向导(New File or Project... > Qt Quick Application
)有一个步骤,您可以选择组件集Select Qt Quick Component Set
)。如果您选择Qt Quick Controls(为了使用ApplicationWindow
而需要),Creator会为您生成正确的代码:
import QtQuick 2.2
import QtQuick.Controls 1.1
ApplicationWindow {
visible: true
width: 640
height: 480
title: qsTr("Hello World")
menuBar: MenuBar {
Menu {
title: qsTr("File")
MenuItem {
text: qsTr("Exit")
onTriggered: Qt.quit();
}
}
}
Text {
text: qsTr("Hello World")
anchors.centerIn: parent
}
}
答案 1 :(得分:2)
您需要从引擎创建的对象创建QQuickWindow。这是我项目中的peace of code:
engine.load(QUrl(QString(String_val(_qmlpath))));
QList<QObject*> xs = engine.rootObjects();
if (xs.count() == 0) {
Q_ASSERT_X(false, "Creating C++ runtime", "Your QML file seems buggy");
}
QQuickWindow *window = qobject_cast<QQuickWindow*>(xs.at(0) );
window->showMaximized();
app.exec();
答案 2 :(得分:0)
如果要在foolscreen模式下显示根对象(Window
或ApplicationWindow
),则可以执行以下操作:
import QtQuick.Window 2.3
import QtQuick.Controls 2.2
ApplicationWindow {
visible: true
visibility: Window.FullScreen
}
visibility
的可能有用值包括:Window.FullScreen
和Window.Windowed
。