Question

我正在使用xmlhttpRequest从数据库中获取数据但它显示错误交叉原始请求仅支持http。我试过＆＃34;标题（＆＃39; Access-Control-Allow-Origin：*＆＃39;）;＆＃34;在PHP但仍显示错误。这是我的HTML代码

    <!DOCTYPE html>
<html>
<head>
<script>
function loadXMLDoc()
{
var xmlhttp;
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    document.getElementById("myDiv").innerHTML=xmlhttp.responseText;
    }
}
xmlhttp.open("GET","devangpatel.host56.com/sample.php",true);
xmlhttp.send();
}
</script>
</head>
<body>

<h2>AJAX</h2>
<button type="button" onclick="loadXMLDoc()">Request data</button>
<div id="myDiv"></div>

</body>
</html>

这里是php

<?php
header('Access-Control-Allow-Origin: *');
$con=mysqli_connect("host","user","password","db");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$result = mysqli_query($con,"SELECT * FROM demo");

while($row = mysqli_fetch_array($result)) {
  echo $row['FirstName'] . " " . $row['LastName'];
  echo "<br>";
}

mysqli_close($con);
?>

只有HTTP错误才支持交叉原始请求

0 个答案: