Question

不确定我在这里做错了什么？程序要求输入文件名并读取文件，但是当打印出编码的消息时，它会显示为空白。我错过了什么，好像我将短语更改为普通的raw_input（“输入消息”）代码将起作用，但这不是从txt文件读取。

letters = "a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]
cshift = int(input("Enter a number: "))
phrase = open(raw_input("file name: "), 'r')
newPhrase = ""
for l in phrase:
   if l in letters:
        pos = letters.index(l) + cshift
        if pos > 25:
            pos = pos-26
        newPhrase += letters[pos]

else:
    newPhrase += " "
print(newPhrase)

Answer 1

这里的问题是这一行的for循环：

for l in phrase:

将返回完整的行，而不是单个字符。

因此，您还必须遍历这些行中的单个字符，或者读取文件二进制文件，或者使用一次读取一个字符的文件对象上的函数。

你可以这样做：

for line in phrase:
    for l in line:
        ... rest of your code here

Answer 2

open函数不返回字符串，而是返回打开文件的句柄，从中可以读取字符串。您应该搜索有关如何在Python中将文件读入字符串的信息，然后在REPL中尝试以确保它返回字符串而不是其他内容。

使用shift加密文件

2 个答案: