Question

我有一个AlertDialog，其视图如下所示。

userEmail = new EditText(mActivity);
userEmail.setSingleLine(true);

userEmail.setHint("Email address");
userEmail.setInputType(InputType.TYPE_TEXT_VARIATION_EMAIL_ADDRESS);
userEmail.addTextChangedListener(this);

AlertDialog.Builder builder = new AlertDialog.Builder(mActivity);
builder.setTitle(getResources().getString(R.string.text_dialog_email));
builder.setView(userEmail);

我已经为事件监听器添加了一个POSITIVE按钮。

builder.setPositiveButton(android.R.string.ok, new DialogInterface.OnClickListener() {
      public void onClick(DialogInterface dialog, int which) {
          if(userEmail.getText().toString().trim().length() <= 0) {
                userEmail.setError("Email address can't be empty");
          } else {
                  //some logic

                 InputMethodManager imm = (InputMethodManager) mActivity.getSystemService(Activity.INPUT_METHOD_SERVICE);
                      imm.hideSoftInputFromWindow(userEmail.getWindowToken(), 0);

                 dialog.dismiss(); 
           }

} });

builder.create();
builder.show();

当用户点击确定按钮时，会有电子邮件验证。如果Edittext为空，我希望对话框保持不变。但是，实际上，即使EditText为空，对话框也会消失。

我缺少什么？

修改

整个代码位于一个方法openEmailDialog（）中。它是在按钮上调用的。

@Override
public void onClick(View view) {
   openEmailDialog();
}

Answer 1

如果您通过构建器添加onClickListener，则对话框将自动关闭。

您可以通过手动将View.OnClickListener添加到对话框的Button视图来阻止此操作。显示后，您可以从对话框中收到Button View。

你应该试试这个：

builder.setPositiveButton(android.R.string.ok, null);//init button
final AlertDialog d = builder.create();//store reference to the dialog
//the click listener for your button
final View.OnClickListener myListener = new View.OnClickListener(){
    public void onClick(View v){
         if(userEmail.getText().toString().trim().length() <= 0) {
            userEmail.setError("Email address can't be empty");
      } else {
              //some logic

             InputMethodManager imm = (InputMethodManager) mActivity.getSystemService(Activity.INPUT_METHOD_SERVICE);
                  imm.hideSoftInputFromWindow(userEmail.getWindowToken(), 0);

             d.dismiss(); 
       }
    }
});

d.setOnShowListener(new DialogInterface.OnShowListener(){

    public void onShow(DialogInterface dialog){
        //here get the Button and set onclicklistener
        Button b = d.getButton(DialogInterface.BUTTON_POSITIVE);
        b.setOnClickListener(myListener);//your validation in your onclicklistener.
        //do not forget to dismiss the dialon in your View.OnClickListener
    } 

});
d.show();

Answer 2

您可以使用Java Reflection解决此问题。

 private void canCloseDialog(DialogInterface dialogInterface, boolean close) {  
     try {  
         Field field = dialogInterface.getClass().getSuperclass().getDeclaredField("mShowing");

         field.setAccessible(true);  
         field.set(dialogInterface, close);  
     } catch (Exception e) {  
         e.printStackTrace();  
     }  
 }

在onClick回调中调用此方法

 new AlertDialog.Builder(this)  
         .setTitle(R.string.abc)  
         .setView(passwdEditText)  
         .setPositiveButton(android.R.string.ok, new DialogInterface.OnClickListener() {  
             @Override  
             public void onClick(DialogInterface dialogInterface, int i) {  
                 canCloseDialog(dialogInterface, false);//will NOT close the Dialog
             }  
         })  
         .setNeutralButton(android.R.string.cancel, new DialogInterface.OnClickListener() {  
             @Override  
             public void onClick(DialogInterface dialogInterface, int i) {  

                 canCloseDialog(dialogInterface, true);//will close the Dialog
             }  
         })  
         .show();

AlertDialog：条件失败时无法保持对话

2 个答案: