Question

我使用CakePHP 2.5.2并且在搜索数据方面遇到了一些麻烦。

在我的申请表中我有3张桌子，球队，球员，技能......团队中有80条记录，玩家2400条记录，技能2400条记录......我想计算一个团队的平均技能。 ..

 //Team model
 public $actsAs = array('Containable');
 public $hasMany = array('Player');

    //Player model
 public $actsAs = array('Containable');
 public $hasOne = array('Skill');
 public $belongsTo = array('Team');

  //Skill model
 public $actsAs = array('Containable');
 public $belongsTo = array('Player');

我的研究是：

$team =  $this->Team->find('all', array(
    'contain' => array(
        'Player' => array(
             'Skill'
        )
    ),
));
   $this->set('team', $team);

给出了预期的结果：

Array
(
    [0] => Array
        (
            [Team] => Array
                (
                    [id] => 1
                    [name] => my_team_name
                )

            [Player] => Array
                (
                    [0] => Array
                        (
                            [id] => 000000419
                            [name] => Name
                            [surname] => Surname
                            [age] => 21
                            [team_id] => 1
                            [Team_id] => 1
                            [Skill] => Array
                                (
                                    [id] => 20
                                    [player_id] => 000000419
                                    [skill] => 599
                                )

                        ), ecc.....

此结构使用至少1680个查询...这对我来说太过分了......

我尝试了另一种方式，只涉及一个查询，返回错误的数据结构，但我需要的所有信息（也是多余的）。不幸的是，按照这种方式，我无法在View中迭代以显示我需要的内容。

$player =  $this->Team->Player->find('all', array(
            'contains' => array(
            'Skill',
            ),

返回

Array
(
    [0] => Array
        (
            [Player] => Array
                (
                    [id] => 000000400
                    [nome] => my_player_name
                    [cognome] => my_player_surname
                    [nation_id] => 380
                    [age] => 29
                    [team_id] => 2
                )


            [Team] => Array
                (
                    [id] => 2
                    [nome] => my_team_name
                )

            [Skill] => Array
                (
                    [id] => 1
                    [player_id] => 000000400
                    [average] => 632
                )

        )

    ecc.

有没有办法在VIEV中迭代以获得每支球队的平均技能？还有其他解决方案吗？

谢谢！

Answer 1

如果可以将CakePHP升级到2.6或更高版本，则可以使用我的插件解决此问题。该插件与ContainableBehavior具有高度兼容性，但会生成更好的查询。我认为find操作只会执行2个查询。如果你尝试的话，我会很高兴的。

https://github.com/chinpei215/cakephp-eager-loader

<强>用法

<强> 1。启用EagerLoader插件

// In your model
$actsAs = ['EagerLoader.EagerLoader'];

如果你害怕加载我的插件会破坏某些地方，你也可以动态启用它。

// On the fly
$this->Team->Behaviors->load('EagerLoader.EagerLoader');

<强> 2。执行相同的查找操作

$this->Team->find('all', ['contain' => ['Player' => ['Skill']]]);

第3。查看查询日志

您将看到查询日志，如下所示：

SELECT ... FROM teams AS Team WHERE 1 = 1;
SELECT ... FROM players AS Player LEFT JOIN skills AS Skill ON Player.id = Skill.player_id WHERE Player.id IN ( ... );

Answer 2

如果你觉得那个查询搜索了那么多表（即模型）那么在使用find（）

unbind

如果要获取表格的某个特定列，请删除通过在find（）中选择"fields"来确定其他列。

CakePhp包含太多查询

2 个答案: