Question

我已经尝试了所有我能想到的但是我的表单中的数据没有插入到MySQL表中。这是我表格的相关部分：

<form id="masteringhtml5_form" action="send_formdata.php" method="POST">
    <label for="heading" class="heading">Health Survey Form</label>
    <fieldset class="fieldset_border">
         <legend class="legend">Personal Information</legend>
        <div>
            <label for="name">Name</label><br>
            <input type="text" name="Firstname" class="name txtinput" placeholder="First" autofocus>
            <input type="text" name="Lastname" class="name txtinput" placeholder="Last">
       </div>
       <!-- other input fields here -->
       <div class="submit">
           <input type="submit" name="submit" class="submit_btn" value="Submit">
       </div>
</form>

这是我的php文件“send_formdata.php”的相关部分：

<?php
mysqli_connect("localhost:3308","root","9gUCFpWmzh");
mysqli_select_db("personal_info");

if(isset($_REQUEST['submit'])) {
    $errorMessage = "";
    $Firstname=$_POST['Firstname'];
    $Lastname=$_POST['Lastname'];
    // other variables and validation here
    if ($errorMessage != "" ) {
        echo "<p class='message'>" .$errorMessage. "</p>" ;
    } else {
        //Inserting record in table using INSERT query
        $insertTB="INSERT INTO `personal_info`.`personal`
        (`Firstname`, `Lastname`, `Dob`, `Gender`, `Saddress`,
        `Aaddress`, `City`, `State`, `Pincode`, `Country`, `Home`,
        `Work`, `Email`) VALUES ('$Firstname', '$Lastname', '$Dob',
        '$Gender', '$Saddress', '$Aaddress', '$City', '$State',
        '$Pincode', '$Country', '$Home', '$Work', '$Email')";
        mysqli_query($insertTB);
    }
}
?>

数据库和表格是正确的。我用“echo $ insertTB”运行脚本，并在浏览器中生成一个完整的查询语句。

Answer 1

将您的PHP代码更改为

$link = mysqli_connect("localhost:3308","root","9gUCFpWmzh")  or die("cannot connect to server !!");
//mysqli_select_db("personal_info");
mysqli_select_db($link,"personal_info");
if(isset($_REQUEST['submit']))
{
    $errorMessage = "";
    $Firstname=$_POST['Firstname'];
    $Lastname=$_POST['Lastname'];
    // other variables and validation here
    if ($errorMessage != "" ) {
        echo "<p class='message'>" .$errorMessage. "</p>" ;
    }
    else{
        //Inserting record in table using INSERT query
        $insertTB="INSERT INTO `personal_info`.`personal`
        (`Firstname`, `Lastname`, `Dob`, `Gender`, `Saddress`,
        `Aaddress`, `City`, `State`, `Pincode`, `Country`, `Home`,
        `Work`, `Email`) VALUES ('$Firstname', '$Lastname', '$Dob',
        '$Gender', '$Saddress', '$Aaddress', '$City', '$State',
        '$Pincode', '$Country', '$Home', '$Work', '$Email')";
        //mysqli_query($insertTB);
        mysqli_query($link,$insertTB) or die(mysqli_error($link));
    }
}

Answer 2

您应该更改插入查询，如下所示

替换

$insertTB="INSERT INTO `personal_info`.`personal`
        (`Firstname`, `Lastname`, `Dob`, `Gender`, `Saddress`,
        `Aaddress`, `City`, `State`, `Pincode`, `Country`, `Home`,
        `Work`, `Email`) VALUES ('$Firstname', '$Lastname', '$Dob',
        '$Gender', '$Saddress', '$Aaddress', '$City', '$State',
        '$Pincode', '$Country', '$Home', '$Work', '$Email')";
        mysqli_query($insertTB);

用

$insertTB="INSERT INTO `personal_info`.`personal`
        (`Firstname`, `Lastname`, `Dob`, `Gender`, `Saddress`,
        `Aaddress`, `City`, `State`, `Pincode`, `Country`, `Home`,
        `Work`, `Email`) VALUES ('".$Firstname."', '".$Lastname."', '".$Dob."',
        '".$Gender."', '".$Saddress."', '".$Aaddress."', '".$City."', '".$State.",
        '".$Pincode."', '".$Country."', '".$Home."', '".$Work."', '".$Email."')";
        mysqli_query($insertTB);

我们必须始终在插入查询中使用'".$address."'编写变量作为标准实践，因为如果我们不能这样写，有时它会在“john's street”等任何字段中传递值时中断查询。所以单引号（'）打破查询，值不插入表，

Answer 3

要调试常规php错误，请在脚本上添加：

error_reporting(E_ALL);
ini_set('display_errors', '1');

调试数据库连接：

$dbCon = mysqli_connect('localhost', 'root', '9gUCFpWmzh', 'personal_info');
if (!$dbCon) { echo 'Connect Error ('.mysqli_connect_errno().')'. mysqli_connect_error(); exit(); }

要调试查询错误，请将mysqli_query（）更改为：

mysqli_query($dbCon, $insertTB) or die(mysqli_error($dbCon));

对于您插入数据库的每个字段，请修改您的查询而不是'$Firstname' 更改为'".mysqli_real_escape_string($dbCon, $Firstname)."'
为你所有的领域做这件事。

表单数据未插入MySQL表

3 个答案: