使用事件

服务器端API提供了一些事件来帮助您。

的OnOpen

在连接客户端并完成握手时调用。

//Hook up the event in the constructor.
public MyController()
{
    this.OnOpen += MyController_OnOpen;
}

void MyController_OnOpen(object sender, OnClientConnectArgs e)
{
    //The connection is open...
}

所以，如果我在VisualStduio.net中执行以下操作

  class MyController : XSocketController
        {
            //Hook up the event in the constructor.
            public MyController()
            {
                this.OnOpen += MyController_OnOpen;
            }

            void MyController_OnOpen(object sender, OnClientConnectArgs e)
            {
                //The connection is open...
            }

        }

MyController_OnOpen和OnClientConnectArgs被警告用红色下划线，这显然意味着没有好处而且无法正常工作。

之前我是一个好的C＃编码器，现在我做了node.js。

我知道他们试图做的是

var myController = XSocketCotroller();

var myController_onOpen = function(obj,e)
                        {
                           // The connection is open...
                        };

myControler.onOpen = myController_onOpen;

很简单，但我不知道如何在C＃中做到这一点。

你可以指教吗？谢谢！

Answer 1

我不得不做

  public class Server : XSocketController
    {
        public Server()
        { 
            this.OnOpen += onOpen; 
        }

        void onOpen(object sender, XSockets.Core.Common.Socket.Event.Arguments.OnClientConnectArgs e)
        {
            this.send("connected");
        }
        public void send(String msg)
        {
            this.send(msg);
        }

    }

发生错误

OnClientConnectArgs e)是不够的。

Answer 2

猜猜你在使用XSockets 3.0.6？但我会为3.0.6和新的4.0编写样本

真的不知道从onOpen发送连接事件，因为服务器会自动发送事件......

你有“服务器”的控制器名称让我感到困惑，无论如何看到。

服务器端

<强> 3.0.6

using XSockets.Core.Common.Socket.Event.Arguments;
using XSockets.Core.XSocket;
using XSockets.Core.XSocket.Helpers;

namespace KenOkabe
{
    public class SampleController : XSocketController
    {
        public SampleController()
        {
            this.OnOpen += SampleController_OnOpen;
        }

        void SampleController_OnOpen(object sender, OnClientConnectArgs e)
        {
            //Send connected topic to client that connected.
            //Just passing a anonymous object with info about the client, but it can be anything serializable..
            this.Send(new {this.ClientGuid, this.StorageGuid},"connected");
        }
    }
}

<强> 4.0

public class SampleController : XSocketController
{
    public SampleController()
    {
        this.OnOpen += SampleController_OnOpen;
    }

    void SampleController_OnOpen(object sender, OnClientConnectArgs e)
    {
        //Send connected topic to client that connected.
        //Just passing a anonymous object with info about the client, but it can be anything serializable..
        this.Invoke(new { this.ConnectionId, this.Context.PersistentId }, "connected");
    }
}

客户端

<强> 3.0.6

var client = new XSocketClient("ws://127.0.0.1:4502/SampleController", "*");
client.OnOpen += (sender, eventArgs) => { Console.WriteLine("OPEN"); };
client.Bind("connected", textArgs => Console.WriteLine(textArgs.data));
client.Open();

<强> 4.0

var client = new XSocketClient("ws://127.0.0.1:4502", "http://localhost", "SampleController");
client.Controller("SampleController").OnOpen += (sender, connectArgs) => Console.WriteLine("OPEN");
client.Controller("SampleController").On("connected",data => Console.WriteLine(string.Format("{0}, {1}", data.ConnectionId, data.PersistentId)));
client.Open();

因此，* *和4. *之间的最大区别在于，您可以在一个插槽上复用多个控制器。

4.0将支持RPC并且使得“已连接”的绑定过时...我们可以使用“Invoke”直接从服务器调用该方法

猜测你是在NodeJS中编写一些自定义客户端，但是你仍然会收到OnOpen数据，而不是自己从控制器上的OnOpen事件中发送它！

此致 Uffe

XSockets.Net Server onOpen事件实现

使用事件

的OnOpen

2 个答案:

服务器端

客户端