假设我有一个XML文件的一部分,其矩阵布局与此类似:
XML中的矩阵
<matrix>
<row1>
<col1>1.00</col1>
<col2>0.00</col2>
<col3>1.00</col3>
<col4>1.00</col4>
</row1>
<row2>
<col1>0.00</col1>
<col2>1.00</col2>
<col3>1.00</col3>
<col4>0.00</col4>
</row2>
</matrix>
并说id最终得到这样的结构:
所需的结构
public struct sMatrix
{
public float m11;
public float m12;
public float m13;
...
public float m23;
public float m24;
}
我应该如何声明这个结构能够通过XmlSerializer反序列化?是否有一些Xml属性我可以给结构中的浮点数告诉他们,例如,m11
是row1的子节点?我试过这个:[XmlElement("matrix/row1/col1")
但它没有用。
答案 0 :(得分:0)
好吧,您可以将矩阵结构的所有字段标记为不可序列化,并引入“行”结构来序列化和反序列化您的行,如下所示:
[Serializable]
public struct sMatrixRow
{
public sMatrixRow(float col1, float col2, float col3, float col4)
{
this.col1 = col1;
this.col2 = col2;
this.col3 = col3;
this.col4 = col4;
}
public float col1;
public float col2;
public float col3;
public float col4;
}
[Serializable]
public struct sMatrix
{
[XmlElement("row1")]
public sMatrixRow Row1
{
get
{
return new sMatrixRow(m00, m01, m02, m03);
}
set
{
this.m00 = value.col1;
this.m01 = value.col2;
this.m02 = value.col3;
this.m03 = value.col4;
}
}
// And so on, for Rows 2 through 4
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m00;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m01;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m02;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m03;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m10;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m11;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m12;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m13;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m20;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m21;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m22;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m23;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m30;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m31;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m32;
[System.NonSerialized, System.Xml.Serialization.XmlIgnore]
public float m33;
}
更新:此方案成功地序列化和反序列化包含类中的以下“矩阵”字段:
<matrix>
<row1>
<col1>2</col1>
<col2>0</col2>
<col3>0</col3>
<col4>0</col4>
</row1>
<row2>
<col1>0</col1>
<col2>2</col2>
<col3>0</col3>
<col4>0</col4>
</row2>
<row3>
<col1>0</col1>
<col2>0</col2>
<col3>2</col3>
<col4>0</col4>
</row3>
<row4>
<col1>0</col1>
<col2>0</col2>
<col3>0</col3>
<col4>1</col4>
</row4>
</matrix>
这就是你想要的吗?
更新:将[XmlElement(“row1”)]添加到Row1(对于其他行也类似),以使行名称缩写。我在这里基本上做的是使用可序列化属性来创建数据的XML可见表示,这些表示与底层字段不同但是同构。