将treeviewitem显示为wpf中的网格行

时间:2014-07-04 07:44:58

标签: c# wpf xaml treeview

基本上需要在wpf :(随机图片)

中使用treeview控件来实现这样的功能

http://blogs.msdn.com/blogfiles/delay/SimpleTreeGridUX.png

节点和子节点具有相同的标头。

我google了很多,但我对wpf的了解并不是那么好。

这是我的父节点类:

 public class Parent : PropertyChangedBase
    {
        public string ParentName { get; set; }
        public BindableCollection<Child> Children { get; set; }
    }

孩子:

public class Child : PropertyChangedBase
{
    public string ChildName { get; set; }
}

我的xaml树视图:

  <TreeView Grid.Row="0" Grid.Column="0" ItemsSource="{Binding Nodes}">
        <TreeView.Resources>
            <HierarchicalDataTemplate DataType="{x:Type projectModels:Parent}" ItemsSource="{Binding Children}">
                <StackPanel>
                    <Grid>
                        <Grid.ColumnDefinitions>
                            <ColumnDefinition Width="20"></ColumnDefinition>
                            <ColumnDefinition Width="Auto"></ColumnDefinition>
                            <ColumnDefinition></ColumnDefinition>
                        </Grid.ColumnDefinitions>
                        <CheckBox Grid.Column="2"></CheckBox>
                        <TextBlock Grid.Column="1" Text="{Binding ParentName}">
                        </TextBlock>
                    </Grid>
                </StackPanel>
            </HierarchicalDataTemplate>
            <DataTemplate DataType="{x:Type projectModels:Child}">
                <StackPanel Orientation="Horizontal">
                    <TextBlock Text="{Binding ChildName}"></TextBlock>
                </StackPanel>
            </DataTemplate>
        </TreeView.Resources>
    </TreeView>

我尝试使用Grid,但很明显它会创建不同的网格,因此我可以在列宽上进行切换。

我尝试How to make gridview a child element of a treeview in wpf application,但他们使用了ListView。它现在不适合我,因为treeviewitem选择功能与我的树视图和后面的代码紧密结合。

有什么想法可以做到吗?感谢。

2 个答案:

答案 0 :(得分:13)

试试这个 的 XAML

  <TreeView x:Name="treeviewList"  ItemsSource="{Binding ManufacturerList}">
    <TreeView.ItemTemplate>
        <DataTemplate>
            <TreeViewItem  ItemsSource="{Binding Models}">
                <TreeViewItem.Header>
                    <Grid Width="350">
                        <Grid.ColumnDefinitions>
                            <ColumnDefinition Width="100"></ColumnDefinition>
                            <ColumnDefinition Width="Auto" MinWidth="50"></ColumnDefinition>
                            <ColumnDefinition ></ColumnDefinition>
                        </Grid.ColumnDefinitions>
                        <TextBlock Text="{Binding Task}" HorizontalAlignment="Left" VerticalAlignment="Center" Grid.Column="0"/>
                        <TextBlock Text="{Binding durationTotal}" Margin="10,0,10,0" HorizontalAlignment="Left" VerticalAlignment="Center"  Grid.Column="1"/>
                        <TextBlock Text="{Binding HeadNote}" HorizontalAlignment="Left"  VerticalAlignment="Center"  Grid.Column="2"/>
                    </Grid>
                </TreeViewItem.Header>
                <TreeViewItem.ItemTemplate>
                    <DataTemplate>
                        <Grid Margin="-20,0,0,0">
                            <Grid.ColumnDefinitions>
                                <ColumnDefinition Width="100"></ColumnDefinition>
                                <ColumnDefinition Width="Auto" MinWidth="50"></ColumnDefinition>
                                <ColumnDefinition></ColumnDefinition>
                            </Grid.ColumnDefinitions>
                            <TextBlock Text="{Binding SubTask}" Margin="10,0,0,0" HorizontalAlignment="Left" VerticalAlignment="Center" Grid.Column="0"/>
                            <TextBlock Text="{Binding Duration}" Margin="10,0,10,0" HorizontalAlignment="Left" VerticalAlignment="Center"  Grid.Column="1"/>
                            <TextBlock Text="{Binding Notes}" HorizontalAlignment="Left" VerticalAlignment="Center"  Grid.Column="2"/>
                        </Grid>
                    </DataTemplate>
                </TreeViewItem.ItemTemplate>
            </TreeViewItem>
        </DataTemplate>
    </TreeView.ItemTemplate>
</TreeView>

c#c​​ode

public class Company
{
    public string Task { get; set; }
    public string durationTotal { get; set; }
    public string HeadNote { get; set; }
    public List<Model> Models { get; set; }
}
public class Model
{
    public string SubTask { get; set; }
    public string Duration { get; set; }
    public string Notes { get; set; }      
}

   List<Company> ManufacturerList = new List<Company>();

        ManufacturerList.Add(new Company()
        {
            Task = "Coding",
            durationTotal = "4",
            HeadNote = "Coding Task",
            Models = new List<Model>()
            {new Model(){SubTask = "Write", Duration = "2", Notes ="It pays the bills" },
            new Model(){SubTask = "Compile", Duration = "1", Notes ="c# or go home" },
            new Model(){SubTask = "Test", Duration = "1", Notes ="works on my m/c" },}
        });


        ManufacturerList.Add(new Company()
        {
            Task = "Communicate",
            durationTotal = "2",
            HeadNote = "Communicate Task",
            Models = new List<Model>()
            {new Model(){SubTask = "Email", Duration = "0.5", Notes ="so much junk mail"  },
            new Model(){SubTask = "Blogs", Duration = "0.25", Notes ="blogs.msdn.com/delay" },
            new Model(){SubTask = "Twitter", Duration = "0.25", Notes ="RT:nothing to report" },}
        });

        treeviewList.ItemsSource = ManufacturerList;

<强>结果

enter image description here

答案 1 :(得分:4)

如果您的代码唯一的问题是每个树视图项呈现不同的网格列宽度,您可以尝试“共享大小范围”功能将它们全部对齐。在TreeView控件中,将Grid.IsSharedSizeScope设置为true: -

然后将SharedSizeGroup添加到所有树视图项目中应具有相同宽度的ColumnDefinition(无论如何,您的第一列定义具有固定宽度,因此不需要它): -

<Grid.ColumnDefinitions>
   <ColumnDefinition Width="20" />
   <ColumnDefinition Width="Auto" SharedSizeGroup="A" />
   <ColumnDefinition SharedSizeGroup="B" />
</Grid.ColumnDefinitions>

值只是用于“命名”列的字符串,可以是您喜欢的任何内容。