Question

$("#id_dept").change(function(){

                $.ajax({
                    type: "GET",
                    url: "GetManager.php",
                    data: "department=" + $(this).find(":selected").val(),  
                    dataType: "text",
                    cache: false,
                    success: function(msg){
                    $("#manager").empty();
                    response = $.parseJSON(msg);

                       for (i = 0; i < response.length; i++) {
                    $("#manager").append("<option value='" + response[i] + "'>" + response[i] + "</option>");

                      }
                      $("#manager").trigger('change');
         }}});
                    $("#id_dept").trigger('change');
});


<tr>
                    <td><label for="id_dept"><b>Department</label></td>
                    <td class='centerPad'>:</td>
                    <td>
                    <select for="id_dept" name="id_dept" id="id_dept">
                            <option value=""></option>


                            <?php


                            $SQL = "select distinct department from Managers";

                            $rs = $conn->Execute($SQL);
                            while (!$rs->EOF) {
                            $a = $rs->Fields("Department")->value;
                            echo "<option value='".$a."'>".$a."</option>";


                            $rs->MoveNext();
                            }
                            ?>
                            </select>
                    </td>
                </tr>
                <tr>
                    <td><label for="manager"><b>Approving Manager</label></td>
                    <td class='centerPad'>:</td>
                    <td>
                    <select for="manager" name="managers" id="manager">
                            <option value=""></option>
                            </select>
                    </td>
                </tr>

上面的代码是form.php。

[PHP]

$dept = $_GET['department'];

$manager = Array();

// SQL查询返回多个数据库记录。

$query = "SELECT * FROM Managers WHERE Department = '".$dept."'"; 

$rs = $conn->Execute($query);

while (!$rs->EOF) {

$manager[] = $rs->Fields(1)->value;

$rs->MoveNext();

}

echo json_encode($manager);

[PHP]

上面的代码是Getmanager.php

现在，当我尝试使用我从AJAX获得的值更新我的表时。

$strSQL = "Select * from Managers where Names='".$manager."'";
$rs = $conn->Execute($strSQL);

未捕获的异常＆＃39; com_exception＆＃39;消息＆＃39;来源：未知说明：未知＆＃39;

这似乎是数据类型的问题。与＆＃34; meta http-equiv =＆＃34; Content-Type＆＃34;相关的内容含量=＆＃34; text / html的;字符集= UTF-8＆＃34;＆＃34;

请帮助！

未捕获的异常'com_exception'，消息'来源：未知描述：未知'

0 个答案: