Question

我希望尝试将返回的直方图放在一起并按分组进行分组，但仅举一个例子，我们说我们的驱动程序很容易导致汽车崩溃。我想知道每个司机每个季度撞毁一辆车的次数，这样我就可以看出他们在整个驾驶过程中是否会变得更糟。

这是一个示例数据表：

crash_date  driver  car
10/26/2013  Jane    Hundo
11/3/2013   Bob     Hundo
11/6/2013   John    Ferd
11/12/2013  John    Superoo
11/12/2013  Bob     Ferd
1/20/2014   John    Superoo
3/5/2014    John    Superoo
3/17/2014   Bob     Superoo
5/24/2014   Bob     Hundo

我想得到的是司机和季度组织的崩溃次数：

Quarter Bob     Jane    John
Q4Y13   2       1       2
Q1Y14   1       0       2
Q2Y14   1       0       0
Q3Y14   0       0       0

使用this question中的信息让我走得很远：

SELECT  crash_year as Year, Count(*) as Bob
FROM    (SELECT  year(crash_date) as crash_year
        FROM    (SELECT DISTINCT crash_date, driver
                FROM            crash_table
                WHERE           driver = "Bob") AS subQuery1) AS subQuery2
GROUP   BY crash_year
ORDER   BY crash_year;

这给了我这个结果：

Year    Bob
2013    2
2014    2

到目前为止，我的搜索没有更多的运气，但我一直在四处寻找。

Answer 1

这适用于动态数量的驱动程序

TRANSFORM Nz(Count(D.driver),0) AS CountOfdriver
SELECT "Q" & DatePart("q",[crash_date]) & "Y" & Year([crash_date]) AS Quarter
FROM Table1 D
GROUP BY "Q" & DatePart("q",[crash_date]) & "Y" & Year([crash_date])
PIVOT D.driver;

输出看起来像这样

Quarter Bob Jane    John
Q1Y2014 1   0       2
Q2Y2014 1   0       0
Q4Y2013 2   1       2

Answer 2

也许这就是你想要的：

select datepart("yyyy", crash_date) as yr, datepart("q", crash_date),
       sum(iif(driver = 'Bob', 1, 0)) as Bob,
       sum(iif(driver = 'Jane', 1, 0)) as Jane,
       sum(iif(driver = 'John', 1, 0)) as John
from crash_table
group by datepart("yyyy", crash_date) , datepart("q", crash_date)
order by 1, 2;

使用Access（SQL）查询按日期对多个字段分组（直方图）数据

2 个答案: