Question

我有两个对象图;

var one = { '1': { id: 1, pid: 1, name: 'John'},
        '3': { id: 35, pid: 3, name: 'Josh'},
        '5': { id: 34, pid: 5, name: 'Joe'} }

var two = {1:1, 34:1, 35:1}

Object.keys(one).forEach(function(item){
    two[one[item].id]= {pid : one[item]};
});

我希望结果为

{1:  { '1': { id: 1, pid: 1, name: 'John'}, 34: {'3': { id: 34, pid: 3, name: 'Josh'}}, 35:{'5': { id: 35, pid: 5, name: 'Joe'}}}

但是我得到了

 {1:  { pid: { id: 1, pid: 1, name: 'John'}, 34: {pid: { id: 34, pid: 3, name: 'Josh'}}, pid:{'5': { id: 35, pid: 5, name: 'Joe'}}}

但我没有动态pid，只有堆栈pid。我知道上面的循环将它设置为静态id，想要解决它以获得动态pid。

Answer 1

为了获得好结果，只需设置＆＃34; pid＆＃34;就像你为＆＃34; id＆＃34;：

所做的一样

var one = { '1': { id: 1, pid: 1, name: 'John'},
        '3': { id: 35, pid: 3, name: 'Josh'},
        '5': { id: 34, pid: 5, name: 'Joe'} }

var two = {}

Object.keys(one).forEach(function(item){
    var current = one[item]
    // We initialize empty object
    two[current.id]= {}
     // We set the object at key .pid to what is wanted
    two[current.id][current.pid] = current
})

console.log(two)

结果（以JSON格式）：

{"1":{"1":{"id":1,"pid":1,"name":"John"}},"34":{"5":{"id":34,"pid":5,"name":"Joe"}},"35":{"3":{"id":35,"pid":3,"name":"Josh"}}}

Answer 2

你所说的你想要的并不是一个有效的对象。我猜你想要

var one = {
    1: { id: 1, pid: 1, name: 'John'},
    3: { id: 35, pid: 3, name: 'Josh'},
    5: { id: 34, pid: 5, name: 'Joe'}
}, two = {};
Object.keys(one).forEach(function(item){
    two[one[item].id]= one[item];
});

Answer 3

var one = { 
    '1': { id: 1, pid: 1, name: 'John'},
    '3': { id: 35, pid: 3, name: 'Josh'},
    '5': { id: 34, pid: 5, name: 'Joe'} 
}

var two = {1:1, 34:1, 35:1}

Object.keys(one).forEach(function(item){
    var obj = {};
    obj[one[item].pid] = one[item];
    two[one[item].id]= obj;
});

console.log (two);

Answer 4

这应该适合你。

var one = { '1': { id: 1, pid: 1, name: 'John'},
    '3': { id: 35, pid: 3, name: 'Josh'},
    '5': { id: 34, pid: 5, name: 'Joe'} };

var two = {1:1, 34:1, 35:1};

for (key in one){
   var item = one[key];
   two[item.id] = {};
   two[item.id][item.pid] = item;
}

如何在对象内设置对象？

4 个答案: