Question

我有一个名为trip的parseobject。我想显示特定用户的行程数据，该用户仅在片段中的任何时间点登录，而不是整个行程表。我正在使用以下代码;

public class TripListAdapter extends ParseQueryAdapter<Trips> {
    SimpleDateFormat formatter = new SimpleDateFormat("MMM dd, yyy");
    public TripListAdapter(Context context) {
        super(context, new ParseQueryAdapter.QueryFactory<Trips>() {
            public ParseQuery<Trips> create() {
                // Here we can configure a ParseQuery to display
                // only top-rated meals.
                ParseUser currentUser = ParseUser.getCurrentUser();
                ParseQuery query = new ParseQuery("Trips");
                query.whereEqualTo("user", currentUser);
                //query.whereContainedIn("rating", Arrays.asList("5", "4"));
                query.orderByDescending("createdAt");
                return query;
            }
        });
    }

    @Override
    public View getItemView(Trips trips, View v, ViewGroup parent) {

        if (v == null) {
            v = View.inflate(getContext(), R.layout.item_trip_list, null);
        }

        super.getItemView(trips, v, parent);

        //ParseImageView mealImage = (ParseImageView) v.findViewById(R.id.icon);
        //ParseFile photoFile = meal.getParseFile("photo");
        //if (photoFile != null) {
            //mealImage.setParseFile(photoFile);
            //mealImage.loadInBackground(new GetDataCallback() {
                //@Override
                //public void done(byte[] data, ParseException e) {
                    // nothing to do
            //  }
            //});
        //}

        TextView destinationTextView = (TextView) v.findViewById(R.id.trip_destination);
        destinationTextView.setText(trips.getDestination());
        TextView durationTextView = (TextView)v.findViewById(R.id.trip_duration);
        durationTextView.setText(formatter.format(trips.getStartDate())+" - "+formatter.format(trips.getEndDate()));
        return v;
    }

但是当我运行应用程序时，我能够看到所有用户创建的数据。我该如何解决？谢谢

Answer 1

我正在做一些非常相似的事情，而且它正在发挥作用。我能看到的唯一区别就是这一行

ParseQuery query = new ParseQuery("Trips");

而不是我做了相同的

ParseQuery<Trips> query = ParseQuery.getQuery(Trips.class);
query.include("user"); // Don't think this will matter

让我知道这是否有效。

Android如何使用ParseQueryAdapter仅显示列表中特定用户的数据

1 个答案: