Question

案例：＆amp;所需的输出

1) string1 = "Multi Axle Volvo SemiSleeper" => o/p true
2) string2 = "Multi Axle Volvo Semi-Sleeper" => o/p true
3) string3 = "Multi Axle Volvo Semisleeper" => o/p true
4) string4 = "Multi Axle Volvo Semi Sleeper" => o/p true
5) string5 = "Multi Axle Volvo Semi sleeper" => o/p true
6) string6 = "Multi Axle Volvo sleeper" => o/p true
7) string7 = "Multi Axle Volvo sleeper" => o/p true
8) string8 = "Multi Axle Volvo" => o/p false

我需要检查所有字符串＆＃39; 睡眠者＆＃39;存在或不存在一个逻辑。

示例：string1 =＆＃34;多轴沃尔沃SemiSleeper＆＃34;在这个＆＃39;睡眠者＆＃39;这个词存在吗？那么真的是假的....就像这样我写了8个案例......

string1.split(' ').map(&:upcase).include?(SLEEPER) => case failing
string1.split(' ').map(&:upcase).include?(SLEEPER) => case Passing

任何帮助/建议......

Answer 1

检查大小写'睡眠者'的一种方法。

str = "Multi Axle Volvo SemiSleeper"
str.downcase.include?('sleeper')
=> true

如何在Ruby中找到字符串中的特定单词？

1 个答案: