Question

我正在撰写一份报告，为我们的新客户带回Landstatus。我们有3个选项（Gold，Silver和Bronze，如果用户没有添加状态，则为null）。数据存储在2个不同的表dbo.tbl_Profile_ProjectLand和dbo.Tasks

中

有时我发现dbo.tbl_Profile_ProjectLand的地位不同于dbo.Tasks

对于我的报告，我想使用dbo.tbl_Profile_ProjectLand作为我的主要表格，如果这对于landstatus没有结果，那么请使用dbo.Tasks

中的landstatus

问题是我似乎无法正确查询。这是我的代码。

SELECT 
Count
            ((CASE WHEN pp.landstatus > 0 THEN pp.landstatus
            ELSE t.landstatus END)) As Taken,
                ls.Description
FROM         dbo.Tasks AS t 
    LEFT JOIN
             tbl_User AS u 
    ON t.TakenBy = u.UserId 
    LEFT JOIN dbo.tbl_Profile_ProjectLand AS pp
ON t.Fk_ProfileID = pp.Fk_ProfileID
    LEFT JOIN
             tbl_DDLandStatus AS ls 
    ON t.LandStatus = ls.Id
    LEFT JOIN 
    dbo.tbl_EnquiryType AS e
    ON t.EnquiryType = e.EnquirytypeId
where
(Month(t.DueDate) = Month(getdate()) 
AND YEAR(t.DueDate) = YEAR(getdate ()))and t.EnquiryType = 1  
GROUP BY 
ls.Description 
ORDER BY ( CASE ls.Description
              WHEN 'Gold - owned' THEN 1
              WHEN 'Silver - identified / offered' THEN 2
              WHEN 'Bronze - no land' THEN 3
              ELSE 0
            END)

这会带来以下结果

Taken   Description
40      NULL
34      Gold - owned
28      Silver - identified / offered
8       Bronze - no land

现在我检查了40个null结果，这是不正确的，因为在中有Null值 dbo.tbl_Profile_ProjectLand表和dbo.Tasks中代表青铜状态的6。

我希望我已经解释过这个好像因为我几乎把自己弄糊涂了。任何帮助将不胜感激。感谢

我找到了一种方法来做到这一点，但我似乎无法将它们分组。这是我的新代码

SELECT 
COUNT ((CASE WHEN pp.landstatus > 0 THEN pp.landstatus
            ELSE t.landstatus END)) As Taken,
((CASE WHEN ls.Description > '' THEN ls.Description
            ELSE lst.description END)) As 'Description'
FROM dbo.Tasks AS t 
LEFT JOIN tbl_DDLandStatus AS lst
    ON t.landstatus = lst.Id 
LEFT JOIN dbo.tbl_Profile_ProjectLand AS pp
    ON t.Fk_ProfileID = pp.Fk_ProfileID
LEFT JOIN tbl_DDLandStatus AS ls 
    ON pp.LandStatus = ls.Id
WHERE (Month(t.DueDate) = Month(getdate()) 
AND YEAR(t.DueDate) = YEAR(getdate ()))and t.EnquiryType = 1  
GROUP BY 
ls.Description,lst.description
ORDER BY ( CASE ls.Description
              WHEN 'Gold - owned' THEN 1
              WHEN 'Silver - identified / offered' THEN 2
              WHEN 'Bronze - no land' THEN 3
              ELSE 0
            END)

这会带回这个结果，这个结果是现场但没有组合。

Taken   Description
22      NULL
7       Bronze - no land
22      Gold - owned
14      Silver - identified / offered
5       Gold - owned
13      Gold - owned
7       Gold - owned
16      Silver - identified / offered
1       Silver - identified / offered
1       Silver - identified / offered
11      Silver - identified / offered

知道如何根据描述对它们进行分组吗？

Answer 1

你可以像这样修改案例并检查

Select count(case when pp.landstatus is not null then pp.landstatus 
              ELSE t.landstatus END) as taken , your query

Answer 2

更改连接的性质以适应状态值的差异是正确的。

我想你也会发现你不需要COUNT（）

中的case表达式

您需要做的就是调整组中的最新查询，以使用您用于描述列的相同案例表达式。

SELECT
      COUNT(*) as Taken
    , ((CASE
            WHEN ls.Description > ''
                  THEN ls.Description
            ELSE lst.description
      END)) AS 'Description'
FROM dbo.Tasks AS t
      LEFT JOIN tbl_DDLandStatus AS lst             ON t.landstatus = lst.Id
      LEFT JOIN dbo.tbl_Profile_ProjectLand AS pp   ON t.Fk_ProfileID = pp.Fk_ProfileID
      LEFT JOIN tbl_DDLandStatus AS ls              ON pp.LandStatus = ls.Id
WHERE (MONTH(t.DueDate) = MONTH(GETDATE())
      AND YEAR(t.DueDate) = YEAR(GETDATE()))
      AND t.EnquiryType = 1
GROUP BY
      (CASE
            WHEN ls.Description > ''
                  THEN ls.Description
            ELSE lst.description
      END)
ORDER BY
      (CASE ls.Description
            WHEN 'Gold - owned'
                  THEN 1
            WHEN 'Silver - identified / offered'
                  THEN 2
            WHEN 'Bronze - no land'
                  THEN 3
            ELSE 0
      END)

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下图：上一次尝试（失败）：不太确定这些：

有两个未引用的表（计数需要？）
案例表达式相当于count（*），我想你需要不包括else，或者做“else NULL”。

试试这个：

SELECT
      COUNT
      (CASE
            WHEN pp.landstatus > 0
                  THEN pp.landstatus
      END)                             AS Taken
    , COALESCE(ls.Description, 'NULL') AS Description
FROM dbo.Tasks AS t
  LEFT JOIN tbl_User AS u                      ON t.TakenBy = u.UserId
  LEFT JOIN dbo.tbl_Profile_ProjectLand AS pp  ON t.Fk_ProfileID = pp.Fk_ProfileID
  LEFT JOIN tbl_DDLandStatus AS ls             ON t.LandStatus = ls.Id
  LEFT JOIN dbo.tbl_EnquiryType AS e           ON t.EnquiryType = e.EnquirytypeId
WHERE (MONTH(t.DueDate) = MONTH(GETDATE())
      AND YEAR(t.DueDate) = YEAR(GETDATE()))
      AND t.EnquiryType = 1
GROUP BY
      COALESCE(ls.Description, 'NULL')
ORDER BY
      (CASE ls.Description
            WHEN 'Gold - owned'
                  THEN 1
            WHEN 'Silver - identified / offered'
                  THEN 2
            WHEN 'Bronze - no land'
                  THEN 3
            ELSE 0
      END)

使用2个表来报告状态SQL查询

2 个答案:

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