Question

我有2个csv文件text1.csv，其中包含： -

1  6  1  1  516405  0  21  8

1  6  1  1  516405  21  8

1  6  1  1  21  34

1  6  1  21  60

text2.csv包含相同的数据： -

1  6  1  1  516405  0  21  8

1  6  1  1  516405  21  8

1  6  1  1  21  34

1  6  1  21  60

比较它们csv文件并以某种方式显示输出的最佳方法是什么： -

Line1 in text1.csv found in Line1 text2.csv
Line2 in text1.csv found in Line2 text2.csv

依此类推，反之亦然。

由于

Answer 1

f1_name = "text1.csv"                                          
f2_name = "text2.csv"                                          
f1 = open(f1_name,'r').readlines()                             
f2 = open(f2_name,'r').readlines()                             

count1 = 0                                                     
for line in f1:                                                
    count1+=1                                                  
    if line != "\n" and line in f2:                            
        print "Line{0} in {1} found in Line{2} in {3} ({4})".format( 
            str(count1),                                       
            f1_name,                                           
            str(1+f2.index(line)),                             
            f2_name,
            line.strip())
f1.close()
f2.close()

<强>输出

Line1 in text1.csv found in Line1 in text2.csv (1  6  1  1  516405  0  21  8)
Line3 in text1.csv found in Line3 in text2.csv (1  6  1  1  516405  21  8)
Line5 in text1.csv found in Line5 in text2.csv (1  6  1  1  21  34)
Line7 in text1.csv found in Line7 in text2.csv (1  6  1  21  60)

Python有效的比较2个csv文件的方法

1 个答案: