Question

所以这几乎就是表格（已经缩小了所需的列）

DATEREGIS ：

10-AUG-95 
02-MAY-01
12-NOV-98
09-OCT-99
12-NOV-98
2-NOV-00
12-AUG-01

我想要做的是创建一个查询以找到最繁忙的月份。

这就是我现在所拥有的，但是它有各种各样的错误，我可以;因为我的生活把这一点弄清楚了。

SELECT 
    dateregistered, count(dateregistered) as count
FROM 
    pet
HAVING 
    count = MAX(count)
GROUP BY 
    dateregistered;

请提供任何帮助。

编辑* DBMS是SQL * Plus

Answer 1

试试这个

Select Month,max(count)
from 
(
SELECT datepart(mm,dateregistered) Month, count(*) as count
FROM pet
Group by datepart(mm,dateregistered);
)t
group by Month

Answer 2

您可以参考此link来了解更多mysql函数。

SELECT MONTHNAME(dateregistered), count(dateregistered) as count
FROM `pet` 
group by MONTH(dateregistered)
order by MONTH(dateregistered) desc

Answer 3

按月分组计数。按递减顺序排序并从此列表中选择第一行。

SELECT *
FROM
(
  SELECT to_char(dateregistered,'mm') as month, count(*) as cnt
  FROM pet
  GROUP BY to_char(dateregistered,'mm')
  ORDER BY count(*) DESC
)
WHERE ROWNUM = 1;

查找一个月的大多数情况

3 个答案: