在一组数组中查找最小和最大时间

Question

我有一个时间阵列，

 var arr= ["17:30:48","19:30:48","18:30:48","19:30:48","17:40:48","19:10:48","17:10:48","19:30:45","17:13:48","19:13:48","17:30:48","19:28:48"];

我想从这些中获得最短和最长时间。尝试了，但是它变得冗长。它有任何简单的方法去做。

Answer 1

看看这个小提琴：http://jsfiddle.net/99Eue/12/

使用此排序功能并抓住第一个元素。这将为您带来最大的收益。

arr.sort(function (a,b) {
    if(a > b) { return -1; }
    if(a < b) { return 1; }    
    return 0;
});

Console.log(arr[0]);

希望这有帮助。

Answer 2

var min = function(arr) {
    return arr.reduce(function(a, b) { return a <= b? a : b;});
};

var max = function(arr) {
    return arr.reduce(function(a, b) { return a <= b? b : a;});
};

reduce速度更快，但可能更好地使用旧的array.sort来提高可读性

Answer 3

var arr= ["17:30:48","19:30:48","17:27:48","19:30:48","17:30:48","19:30:48","17:30:48","19:30:48","17:30:48","19:30:48","17:30:48","19:30:48"];

arr.sort(function (a, b) {
  return new Date('1970/01/01 ' + a) - new Date('1970/01/01 ' + b);
});

alert("Min: " + arr[0] + "     Max: " + arr[arr.length-1]);