如何使用cURL从文件中读取标头?

时间:2014-07-02 21:32:11

标签: linux shell curl

我找到了this

我写了这个变种:

#!/bin/bash
while read line ; do
  headers="$headers -H '$line'"
done < public/headers.txt
echo $headers
curl -X PUT \
     $headers \
     -d @'public/example.json' \
     echo.httpkit.com

headers.txt我有:

X-PAYPAL-SECURITY-USERID:123
X-PAYPAL-SECURITY-PASSWORD:123

但是当我运行./public/curl.sh时,我没有收到我发送的标题。

我用env var隔离了这个问题:

$ x='-H some:asd'
$ curl $x echo.httpkit.com
=> header was NOT present
$ curl -H 'some:asd' echo.httpkit.com
=> header was present
$ curl -H some:asd echo.httpkit.com
=> header was present

如何在标题部分正确插入变量?

2 个答案:

答案 0 :(得分:5)

我们问shellcheck

In yourscript line 3:
  headers="$headers -H '$line'"
                       ^-- SC2089: Quotes/backslashes will be treated literally. 
                                   Use an array.

好的,那就让我们这样做:

#!/bin/bash
while read line ; do
headers=("${headers[@]}" -H "$line")
done < public/headers.txt
echo "${headers[@]}"
curl -X PUT \
   "${headers[@]}" \
   -d @'public/example.json' \
   echo.httpkit.com

结果:

{
  "method": "PUT",
  "uri": "/",
  "path": {
    "name": "/",
    "query": "",
    "params": {}
  },
  "headers": {
    "host": "echo.httpkit.com",
    "user-agent": "curl/7.35.0",
    "accept": "*/*",
    "x-paypal-security-userid": "123",      //      <----- Yay!!
    "x-paypal-security-password": "123",
    "content-length": "32",
    "content-type": "application/x-www-form-urlencoded"
  },
  "body": "\"This is text from example.json\"",
  "ip": "127.0.0.1",
  "powered-by": "http://httpkit.com",
  "docs": "http://httpkit.com/echo"
}

答案 1 :(得分:1)

如果您不想将HTTP标头放在命令行上(可能出于安全原因),您仍然可以直接从文件中读取它们。

curl -H @headerfile.txt https://www.google.com/  # requires curl >=7.55.0

如果您的卷曲早于7.55.0:

  • 使用选项-K/--config <config file>,并在文本文件中添加多条-H/--header <header>行。

有关详细信息,请参阅原始文章中的答案:

https://stackoverflow.com/a/48762561/5201675