来自不同表的数据具有相同的名称，如何检索数据？

Question

这是我的代码：

$sql = "SELECT table1.Insert_ID, table1.Type, table1.Date "
    . "table2.User, table2.Date "
    . "FROM Insert AS table1 "
    . "INNER JOIN Contact AS table2 ON table2.Contact_ID = table1.Contact_ID";

$x =0;

while($row = odbc_fetch_array($res)){

$x++;

 $values= ($x . ": " . " Insert ID:". $row['Insert ID'] . " Date Created: " . $row['Date'] . " Date Modified:" . "\n");

print($values);


}

我想要table1和table2中的Date，如果它们都具有相同的名称，我该如何继续检索数据？

Answer 1

使用别名。

SELECT table1.Insert_ID, table1.Type, table1.Date as Date1 "
. "table2.User, table2.Date as Date2 "
. "FROM Insert AS table1 "
. "INNER JOIN Contact AS table2 ON table2.Contact_ID = table1.Contact_ID";

Answer 2

列别名。

$sql = "SELECT table1.Insert_ID, table1.Type, table1.Date as T1Date "
    . "table2.User, table2.Date as T2Date"
    . "FROM Insert AS table1 "
    . "INNER JOIN Contact AS table2 ON table2.Contact_ID = table1.Contact_ID";