Question

如何从表单中获取值$ val1，$ val2？

可能需要使用类似于此的设计：

$obj->Calculator($_POST['val1'], $_POST['val1']);

但是..在哪里粘贴？

<?php
class Calculator {
    private $_val1 , $_val2;

    public function __construct($val1, $val2){
        $this->_val1 = $val1;
        $this->_val2 = $val2;
    }

    public function add(){
        return $this->_val1 + $this->_val2;
    }

    public function subtract(){
        return $this->_val1 - $this->_val2;
    }

    public function multiply (){
        return $this->_val1 * $this->_val2;
    }

    public function divide () {
        return $this->_val1 / $this->_val2;
    }
}

$calc = new Calculator(3,4);
echo "<p>3 + 4 = ".$calc->add(). "</p>";
?>

<html>
    <head>
        <title>Calculator</title>
    </head>
    <body>
    <form action='' method='POST'>
    Enter Number:
    <input type='text' name='val1' value="<?=$val1;?>">
    <input type='text' name='val2' value="<?=$val2;?>">
    <input type='submit' name='submit' value='Calculate'>
    </form>
    </body>
</html>

Answer 1

您可以使用以下内容：

$val1 = (int) $_POST['val1'];
$val2 = (int) $_POST['val2'];

$calc = new Calculator($val1, $val2);
echo '<p>'.$val1.' + '.$val2.' = '.$calc->add().'</p>';

编辑：您还可以在构造函数中键入强制转换变量：

class Calculator {
    private $_val1 , $_val2;

    public function __construct($val1, $val2){
        $this->_val1 = (int) $val1;
        $this->_val2 = (int) $val2;
    }

    ...
}

$val1 = $_POST['val1'];
$val2 = $_POST['val2'];

$calc = new Calculator($val1, $val2);
echo '<p>'.$val1.' + '.$val2.' = '.$calc->add().'</p>';

Answer 2

别忘了使用

is_numeric($val1);

检查输入是否为数字。

了解更多 php.net is_numeric

从表单中获取值（OOP php）

2 个答案: